Max Sum Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 193355 Accepted Submission(s): 45045 Problem Description Given a sequence a[1],a[2],a[3]--a[n], your job is to calculate the max sum of a su…

Max Sum Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 330535    Accepted Submission(s): 78678 Problem Description Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max su…

原创 http://acm.hdu.edu.cn/showproblem.php?pid=1003 题目要求求出一个序列里面的最大序列和,序列要求是连续的,给出最大序列和,序列首元素下标和尾元素下标,按特定的格式输出. 解题思路: 动态规划,我们可以将所有序列按以序列中的元素a[i](i=1~n)结尾进行分类,比如: 以a[1]结尾的序列有:a[1] 以a[2]结尾的序列有:a[1]a[2],a[2] 以a[3]结尾的序列有:a[1]a[2]a[3],a[2][3],a[3] ......  这…

解题思路: 本题在给定的集合中找到最大的子集合[子集合:集合的元素的总和,是所有子集合中的最大解.] 结果输出: 最大的子集合的所有元素的和,子集合在集合中的范围区间. 依次对元素相加,存到一个 sum 中,同时ans=sum;定义左右边界 left,right;临时左边界ll=1; 如果sum>ans,则ans=sum; 左边界 left=tem; right=i+1; 如果sum<0,则sum=0; tem=i+2; Ac code: #include<bits/stdc++.h&g…

http://acm.hdu.edu.cn/showproblem.php?pid=1003 给出一个包含n个数字的序列{a1,a2,..,ai,..,an},-1000<=ai<=1000 求最大连续子段和及其起始位置和终止位置,很基础的动态规划(DP)问题,看完DP第一次做的DP题目 DP真的是一种很优美的算法,或者说思想,但是比较难理解,我对DP的理解还很浅薄 # include <stdio.h> # define INF 1000000000 int main() { i…

Max Sum Plus Plus Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 29942    Accepted Submission(s): 10516 Problem Description Now I think you have got an AC in Ignatius.L's "Max Sum" problem…

Max Sum Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 250714    Accepted Submission(s): 59365 Problem Description Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max su…

HDU 1024 Max Sum Plus Plus (动态规划) Description Now I think you have got an AC in Ignatius.L's "Max Sum" problem. To be a brave ACMer, we always challenge ourselves to more difficult problems. Now you are faced with a more difficult problem. Given…

Max Sum Plus Plus Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 44371    Accepted Submission(s): 16084 Problem Description Now I think you have got an AC in Ignatius.L's "Max Sum" problem…

题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=1024 Problem Description Now I think you have got an AC in Ignatius.L's "Max Sum" problem. To be a brave ACMer, we always challenge ourselves to more difficult problems. Now you are faced with a mor…