Splitting Pile Time limit : 2sec / Memory limit : 256MB Score : 300 points Problem Statement Snuke and Raccoon have a heap of N cards. The i-th card from the top has the integer ai written on it. They will share these cards. First, Snuke will take so…

题目描述 Snuke and Raccoon have a heap of N cards. The i-th card from the top has the integer ai written on it.They will share these cards. First, Snuke will take some number of cards from the top of the heap, then Raccoon will take all the remaining car…

C - Splitting Pile Time limit : 2sec / Memory limit : 256MB Score : 300 points Problem Statement Snuke and Raccoon have a heap of N cards. The i-th card from the top has the integer ai written on it. They will share these cards. First, Snuke will tak…

我好菜啊,ARC注定出不了F系列.要是出了说不定就橙了. C - Splitting Pile 题意:把序列分成左右两部分,使得两边和之差最小. #include<cstdio> #include<algorithm> #define MN 2100001 using namespace std; int n,m,a[MN]; ,sum2=,mmh=1e18; ?-x:x;} int main(){ scanf("%d",&n); ;i<=n;i+…

C - Splitting Pile 枚举从哪里开始分的即可 #include <bits/stdc++.h> #define fi first #define se second #define pii pair<int,int> #define mp make_pair #define pb push_back #define space putchar(' ') #define enter putchar('\n') #define MAXN 200005 #define e…

C - Splitting Pile Time limit : 2sec / Memory limit : 256MB Score : 300 points Problem Statement Snuke and Raccoon have a heap of N cards. The i-th card from the top has the integer ai written on it. They will share these cards. First, Snuke will tak…

在 Bash manual 里叫 Word Splitting,在 Posix 规范里叫 Field Splitting,这两者指的是同一个东西,我把它翻译成“分词”,下面我就说三点很多人都忽略掉(或者说从没仔细考虑过)的分词细节. 1. 分隔符到底是字符还是字符串? IFS 里面可以包含多个字符,那么在分词的过程中,是 IFS 中的每个单独的字符作为分隔符,还是由这些字符组合成的任意字符串作为分隔符?我们写个简单的例子证明一下: $ var=a12b21c IFS=12 $ printf "&…

A. The Text Splitting 题目连接: http://www.codeforces.com/contest/612/problem/A Description You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q. For example, the string "Hello" for p = 2, q = 3…

2365: Splitting the Field 题意:n个点,求用两个矩形面积覆盖完所有点和一个矩形覆盖完少多少面积 思路:枚举两个矩形的分割线,也就是把所有点分成两个部分,枚举分割点:先预处理每个点之前和之后的最大,最低高度: 矩形可以横着分,也可以竖着分 // #pragma comment(linker, "/STACK:102c000000,102c000000") #include <iostream> #include <cstdio> #inc…

As a Single Page Application grows in size, the size of the payload can become a real problem for performance. In this lesson, learn how to leverage code splitting to easily implement lazy loading for your application to load only the code necessary…