[BZOJ3872][Poi2014]Ant colony 试题描述 There is an entrance to the ant hill in every chamber with only one corridor leading into (or out of) it. At each entry, there are g groups of m1,m2,...,mg ants respectively. These groups will enter the ant hill one…

3872: [Poi2014]Ant colony Time Limit: 30 Sec  Memory Limit: 128 MB Description   There is an entrance to the ant hill in every chamber with only one corridor leading into (or out of) it. At each entry, there are g groups of m1,m2,...,mg ants respecti…

[BZOJ3872][Poi2014]Ant colony Description 给定一棵有n个节点的树.在每个叶子节点,有g群蚂蚁要从外面进来,其中第i群有m[i]只蚂蚁.这些蚂蚁会相继进入树中,而且要保证每一时刻每个节点最多只有一群蚂蚁.这些蚂蚁会按以下方式前进: ·在即将离开某个度数为d+1的点时,该群蚂蚁有d个方向还没有走过,这群蚂蚁就会分裂成d群,每群数量都相等.如果d=0,那么蚂蚁会离开这棵树. ·如果蚂蚁不能等分,那么蚂蚁之间会互相吞噬,直到可以等分为止,即一群蚂蚁有m只,要分成…

线段树求某一段的GCD..... F. Ant colony time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Mole is hungry again. He found one ant colony, consisting of n ants, ordered in a row. Each ant i (1 ≤ i ≤ n)…

F. Ant colony time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Mole is hungry again. He found one ant colony, consisting of n ants, ordered in a row. Each ant i (1 ≤ i ≤ n) has a strength si…

[BZOJ3872]Ant colony(二分,动态规划) 题面 又是权限题... Description There is an entrance to the ant hill in every chamber with only one corridor leading into (or out of) it. At each entry, there are g groups of m1,m2,...,mg ants respectively. These groups will ent…

Ant colony 题解: 因为一个数是合法数,那么询问区间内的其他数都要是这个数的倍数,也就是这个区间内的gcd刚好是这个数. 对于这个区间的gcd来说,不能通过前后缀来算. 所以通过ST表来询问这个区间的gcd. 那么题目就变成了询问一个区间内有多少个k. 我们对于每个数都离散化之后,在相应的数字存下下标. 然后二分一下个数. 代码: #include<bits/stdc++.h> using namespace std; #define Fopen freopen("_in.…

题目描述: F. Ant colonytime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard output Mole is hungry again. He found one ant colony, consisting of n ants, ordered in a row. Each ant i (1 ≤ i ≤ n) has a strength si.…

题目大意: 给定一棵$n(n\le10^6)$个结点的树.在每个叶子结点,有$g$群蚂蚁要从外面进来,其中第$i$群有$m_i$只蚂蚁.这些蚂蚁依次爬树(一群蚂蚁爬完后才会爬另一群),若当前经过结点度为$d+1$,蚂蚁数量为$m$,则接下来没走过的$d$个方向,每个方向爬$\lfloor\frac md\rfloor$只蚂蚁,剩下蚂蚁消失.在给定的一条边上有一只食蚁兽,若当前经过这条边的蚂蚁数量为$k$,则吃掉这些蚂蚁.问最后能吃到多少蚂蚁? 思路: 从给定边出发BFS,算出每条边会被吃掉的蚁群…

题目:https://www.lydsy.com/JudgeOnline/problem.php?id=3872 可以倒推出每个叶子节点可以接受的值域.然后每个叶子二分有多少个区间符合即可. 注意一开始的两个点不是直接是 l[ u ]=r[ u ]=lm !也要看度数的!且把那条边的两个端点分别算子树很方便. 而且过程中似乎会爆 long long ,所以如果 l[ i ] 都大于最大值就不往下算了:r[ i ]也要每次与最大值取min. 然后是和网上一份题解对拍出错却仍A了此题的代码.不想管是…