poj 2601 Simple calculations】的更多相关文章

Simple calculations Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6559   Accepted: 3291 Description There is a sequence of n+2 elements a0, a1, ..., an+1 (n <= 3000, -1000 <= ai <=1000). It is known that ai = (ai-1 + ai+1)/2 - ci f…
推公式/二分法 好题! 题解:http://blog.csdn.net/zck921031/article/details/7690288 这题明显是一个方程组……可以推公式推出来…… 然而这太繁琐了!发现a[i]是满足单调性的话,我们就可以二分a[1],递推出a[n+1],进行验证…… 思维复杂度比推公式低到不知哪里去了,真是一种优秀的算法(然而我想不到,并没有什么*用……) Source Code Problem: User: sdfzyhy Memory: 736K Time: 16MS…
UVA - 10014 Simple calculations Time Limit: 3000MS Memory Limit: Unknown 64bit IO Format: %lld & %llu id=19100" style="color:blue">Submit Status Description  Simple calculations  id=19100" style="color:blue">The Pro…
题目:http://poj.org/problem?id=3468   A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 85851   Accepted: 26685 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with…
A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 105742   Accepted: 33031 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type o…
A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 112228   Accepted: 34905 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type o…
题目链接 A Sample Stone Game 题目大意:给定n,k,表示最初时有n个石头,两个人玩取石子游戏,第一个人第一次可以取1~n-1个石头,后面每个人最多可以拿走前面一个人拿走的个数的K倍,当有一个人可以一次性全部拿走时获胜.问两人都在不失误的情况下,先拿着有没有必胜局势.有的话求他第一次最少该取多少个. 思考过程: 首先讨论k=1的情况,我们可以把一个数n(石子的个数),写为二进制下的表示,那先者取走最后一个1,那后者必然不能取走比它高一位的1,那么先拿者一定会赢,当然如果n本来就…
http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=955 根据递推公式推倒出a1的公式. a1=(n*a0+an+1-2*(n*c1+(n-1)*c2+...+cn))/(n+1); #include <cstdio> #include <cstring> #include <algorithm> #defi…
#include<iostream> #include<iomanip> #include<stdio.h> using namespace std; int main() { //freopen("acm.acm","r",stdin); int n; int i; double * a; double * c; cin>>n; a = ]; c = new double[n]; cin>>a[]>…
You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of numbers in a given interval. Input The firs…
#include<cstdio> #include<algorithm> #include<cstring> typedef long long ll; #define N 100010 using namespace std; struct node { ll l,r,lz,sum; }t[*N]; ll read() { ll ret=,neg=; char j=getchar(); ';j=getchar()) ; ';j=getchar()) ret=ret*+…
Description 有一个包括n+2个元素的数列a0, a1, ..., an+1 (n <= 3000, -1000 <= ai <=1000).它们之间满足ai = (ai-1 + ai+1)/2 - ci (i=1, 2, ..., n).如今给出a0, an+1, c1, ... , cn..请编敲代码计算出a1. Input 输入的第一行是一个整数n. 接下去的两行各自是a0和an+1,(精确到小数点后两位)再接下去的n行是ci(精确到小数点后两位).每一个数字占一行. O…
完全不知道该怎么用,看书稍微懂了点. 题意: 给定序列及操作,求区间和. 分析: 树状数组可以高效的求出连续一段元素之和或更新单个元素的值.但是无法高效的给某一个区间的所有元素同时加个值. 不能直接用树状数组求,就处理一下.用两个树状数组维护两个数据,一个维护前i项和,一个维护增加的值.设: ∑j=1iaj=sum(bit1,i)∗i+sum(bit0,i) 那么[l,r]区间上同时加上x就可以表示为: 对于bit0来说,在l位置上加上−x∗(l−1),在r+1位置上加上x∗r 对于bit1来说…
题意: 给定序列及操作,求区间和. 分析: 线段树,每个节点维护两个数据: 该区间每个元素所加的值 该区间元素和 可以分为"路过"该区间和"完全覆盖"该区间考虑. 代码: #include<cstdio> #include<iostream> #include<cmath> using namespace std; typedef long long ll; //[l,r) const int maxn = 300005; ll…
Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of numbers in a given interval. In…
Send a TableInput: Standard Input Output: Standard Output When participating in programming contests, you sometimes face the following problem: You know how to calcutale the output for the given input values, but your algorithm is way too slow to eve…
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Sorting, filtering, paging, and grouping 7 of 8 people found this helpful By Tom Dykstra The Contoso University sample web application demonstrates how to create ASP.NET Core 1.0 MVC web applications using Entity Framework Core 1.0 and Visual Studio…
Send a Table Input: Standard Input Output: Standard Output When participating in programming contests, you sometimes face the following problem: You know how to calcutale the output for the given input values, but your algorithm is way too slow to ev…
send a table When participating in programming contests, you sometimes face the following problem: You knowhow to calcutale the output for the given input values, but your algorithm is way too slow to everpass the time limit. However hard you try, yo…
除1,1其他外国x,y不等于 为 x<y 案件 一切y有phi(y)组合 F[x]= phi(i) 2<=i<=x 结果为 2*F[x]+1 Problem A Send a Table Input: Standard Input Output: Standard Output When participating in programming contests, you sometimes face the following problem: You know how to calc…
ckediter ##<link rel='stylesheet' href='/css/index.css' /> <script type="text/javascript" src="/ckeditor/ckeditor.js"></script> <textarea name="editor1" id="editor1" rows="10" cols=&qu…
计算机科学及编程导论在 MIT 的课程编号是 6.00.1,是计算机科学及工程学院的经典课程.之前,课程一直使用 Scheme 作为教学语言,不过由于 Python 简单.易学等原因,近年来已经改用 Python 作为教学语言了.更多介绍 最初知道这个课程的时候大概是在 2014 年,对于做事拖沓的我,这门课程已经从低清随堂录制变成了 edX 平台的一门 高清的 MOOC,转眼间已经大三,希望自己能够完成自己曾经定下的计划.以下是在我在学习本课程时的一些笔记,在此与大家共享.共勉. What d…
Introduction to text manipulation on UNIX-based systems https://www.ibm.com/developerworks/aix/library/au-unixtext/index.html     A basic tenets of UNIX philosophy is to create programs (or processes) that do one thing, and do that one thing well. It…
When participating in programming contests, you sometimes face the following problem: You know how to calcutale the output for the given input values, but your algorithm is way too slow to ever pass the time limit. However hard you try, you just can’…
参考:http://www.design-reuse.com/articles/24503/nand-flash-memory-embedded-systems.html Abstract : This paper presents fundamental information about NAND Flash memory used in Embedded Systems. It discusses various aspects of this storage media such as…
原文:https://html5.litten.com/how-to-drag-and-drop-on-an-html5-canvas/ 下面作者的原始的版本会抖动一下(鼠标刚点下去的时候,位置会发生一下突变,不是很友好), 我修改了 一下. var xDown , yDown;function myDown(e){ if (e.pageX < x + 15 + canvas.offsetLeft && e.pageX > x - 15 + canvas.offsetLeft…
Description When participating in programming contests, you sometimes face the following problem: You know how to calcutale the output for the given input values, but your algorithm is way too slow to ever pass the time limit. However hard you try, y…
本文转自:http://www.asp.net/mvc/overview/older-versions/getting-started-with-ef-5-using-mvc-4/sorting-filtering-and-paging-with-the-entity-framework-in-an-asp-net-mvc-application Download Completed Project The Contoso University sample web application de…
An apparatus comprising a plurality of storage nodes comprising a plurality of corresponding storage disks and configured to store data in a distributed manner between the storage disks that achieves a Redundant Array of Independent Disks-0 (RAID0) l…