Pyramid Split Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://bestcoder.hdu.edu.cn/contests/contest_chineseproblem.php?cid=629&pid=1001 Description 小明是城会玩,他有很多底面是正方形的黄金锥体,我们称之为金字塔,它由高度和底面正方形边长可以确定,分别称之为金字塔的高和宽. 为了便于理解,单位统一取米.现在小明有nn个金字塔,已知它们的高和宽,小…

Problem Description Xiao Ming is a citizen who's good at playing,he has lot's of gold cones which have square undersides,let's call them pyramids. Anyone of them can be defined by the square's length and the height,called them width and height. To ea…

题意:有n个底面是正方形的四棱锥,用一个水平截面将所有四棱锥分成两半,要求上一半体积的和等于下一半,求水平截面的高度,输出整数部分. 解法:二分截面高度.比赛的时候二分写不明白了orz…… 代码: #include<stdio.h> #include<iostream> #include<algorithm> #include<string> #include<string.h> #include<math.h> #include&l…

http://acm.hdu.edu.cn/showproblem.php?pid=5423 题目大意:给你一个树 判断这棵树是否是独特的 一颗树是独特的条件:不存在一颗和它本身不同但相似的树 两颗树相似条件:两颗树中点的数量相等且相对应的点的深度相同 如第2个样例 4 1 2 2 3 1 4 与 4 1 2 1 4 3 4 如图:这两棵树的点的数量相等且相应的点的深度deep相同,所以这两棵树相似,所以样例2存在一颗树与它不同但相似,即不特殊 运用广搜统计每个点的深度 要想一颗树特殊,只有保证…

Problem Description Xiao Ming is a citizen who's good at playing,he has lot's of gold cones which have square undersides,let's call them pyramids. Anyone of them can be defined by the square's length and the height,called them width and height. To ea…

Problem Description As we know, Rikka is poor at math. Yuta is worrying about this situation, so he gives Rikka some math tasks to practice. There is one of them: For a tree T , let F(T,i) be the distance between vertice 1 and vertice i .(The length…

Pyramid Split Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 104    Accepted Submission(s): 50 Problem Description Xiao Ming is a citizen who's good at playing,he has lot's of gold cones which…

​ 前言: 前面分享了一篇<继SE,CBAM后的一种新的注意力机制Coordinate Attention>,其出发点在于SE只引入了通道注意力,CBAM的空间注意力只考虑了局部区域的信息,从而提出考虑全局空间信息的注意力机制. 在本文,将介绍另一个基于同样出发点的注意力模块,即Pyramid Split Attention (PSA).PSA具备即插即用.轻量.简单高效的特点.该模块与ResNet结合,通过PSA替代ResNet的bottleneck中的3x3卷积,组成了EPSANet. E…

意甲冠军:非常多,形成一个金字塔球 文章x层 x*(x+1)/ 2 球 给你个S 金字塔的一层代表第一数字向下S球 它是其中  这层中的第几行 第几列 公式 1 : x*(x+1)*(x+2)/ 6 公式 2 :x*(x+1)/ 2 公式1为公式2 的前n项和 #include <cstdio> #include <cstring> #include <cstdlib> #include <string> #include <iostream>…

链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=2191 思路:多重背包模板题 #include <stdio.h> #include <stdlib.h> #include <string.h> #include <math.h> #include <algorithm> using namespace std; int money,type; ],weigh[],num[],dp[]; i…