hdu 1040 As Easy As A+B】的更多相关文章

As Easy As A+B Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 53368    Accepted Submission(s): 22939 Problem Description These days, I am thinking about a question, how can I get a problem as…
As Easy As A+B Problem Description These days, I am thinking about a question, how can I get a problem as easy as A+B? It is fairly difficulty to do such a thing. Of course, I got it after many waking nights.Give you some integers, your task is to so…
今天去老校区找她,不想带电脑了,所以没时间A题了 /*******************************************************************/ As Easy As A+B Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 45926    Accepted Submission(s): 196…
As Easy As A+B Problem Description These days, I am thinking about a question, how can I get a problem as easy as A+B? It is fairly difficulty to do such a thing. Of course, I got it after many waking nights. Give you some integers, your task is to s…
题意:给定n个数,让你从小到大排序. 析:不说什么了. 代码如下: #include <cstdio> #include <iostream> #include <cstring> #include <algorithm> #include <cmath> using namespace std; const int maxn = 1000 + 5; int a[maxn]; int main(){ int T, n; cin >>…
题意:裸排序 思路:排序 #include<iostream> #include<stdio.h> #include<algorithm> using namespace std; ]; int main(){ int t,n,i; scanf("%d",&t); while(t--){ scanf("%d",&n); ;i<n;++i) scanf("%d",&a[i]); so…
HDU 5572 An Easy Physics Problem (计算几何) 题目链接http://acm.hdu.edu.cn/showproblem.php?pid=5572 Description On an infinite smooth table, there's a big round fixed cylinder and a little ball whose volume can be ignored. Currently the ball stands still at p…
题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5058 So easy Description Small W gets two files. There are n integers in each file. Small W wants to know whether these two files are same. So he invites you to write a program to check whether these two…
http://acm.hdu.edu.cn/showproblem.php?pid=5475 An easy problem Time Limit: 8000/5000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 755 Accepted Submission(s): 431 Problem Description One day, a useless calculator was…
An easy problem Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5475 Description One day, a useless calculator was being built by Kuros. Let's assume that number X is showed on the screen of calculator. At first,…
An Easy Problem for Elfness Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 1148    Accepted Submission(s): 234 Problem Description Pfctgeorge is totally a tall rich and handsome guy. He plans t…
So Easy [题目链接]So Easy [题目类型]矩阵解公式 &题解: 感觉这种类型的题都是一个套路,这题和hdu 2256就几乎是一样的. 所以最后2Xn就是答案 [时间复杂度]\(O(logn)\) &代码: #include <cstdio> #include <bitset> #include <iostream> #include <set> #include <cmath> #include <cstrin…
http://acm.hdu.edu.cn/showproblem.php?pid=2132 Problem Description We once did a lot of recursional problem . I think some of them is easy for you and some if hard for you.Now there is a very easy problem . I think you can AC it.  We can define sum(n…
so easy 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5650 Description Given an array with n integers, assume f(S) as the result of executing xor operation among all the elements of set S. e.g. if S={1,2,3} then f(S)=0. your task is: calculate xor…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1040 解题思路:数据不大,可以直接用冒泡排序 #include<stdio.h> int main() { int ncase,n; int i,j; int a[1000]; int t; while(scanf("%d",&ncase)!=EOF) { while(ncase--) { scanf("%d",&n); for(i=0;i&…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4565 题意: 题意: #include <iostream>#include <cstdio>#include <string.h>#include <algorithm>#include <cmath>#include <vector>#include <queue>#include <set>#include…
So Easy! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3459    Accepted Submission(s): 1113 Problem Description A sequence Sn is defined as: Where a, b, n, m are positive integers.┌x┐is the ce…
So Easy! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3804    Accepted Submission(s): 1251 Problem Description A sequence Sn is defined as: Where a, b, n, m are positive integers.┌x┐is the ce…
Problem Description We once did a lot of recursional problem . I think some of them is easy for you and some if hard for you. Now there is a very easy problem . I think you can AC it. We can define sum(n) as follow: if i can be divided exactly by 3 s…
2015上海区域赛现场赛第5题. 题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=5572 题意:在平面上,已知圆(O, R),点B.A(均在圆外),向量V. 一个小球从A出发,沿速度向量V匀速前进,若撞到圆则发生弹性碰撞,沿“反射方向”继续匀速前进.问A点能否经过B点. 题目读懂了,把所有情况都考虑全,流程图就出来了,然后直接套模版即可(注意有些功能可剪裁~) 我的第一道计算几何,WA了一个星期啊...原因有姿势不对,精度不对,还有输出不对的. 不…
转载请注明出处,谢谢http://blog.csdn.net/ACM_cxlove?viewmode=contents    by---cxlove 题意:给出一个带边权的图.对于每一个询问(S , T , K , A , B),有两种操作,加一条单位边花费为A,将某条边流量扩展一个单位花费为B,在预算为K的情况下求S到T最大流的最大值. http://acm.hdu.edu.cn/showproblem.php?pid=4729 做法:如果A <= B,很明显只做添加边操作,而且只加在S -…
问题: 開始尝试用字符做数组元素.可是并没实用. 在推断语句时把a z排出了. An easy problem Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 16516    Accepted Submission(s): 11096 Problem Description we define f(A) = 1, f(a) = -1,…
问题: 使用double定义的数量和long数定义19-20出现分歧,原因不明.求大公社. 这个问题需要用long,否则,只是通过,这应该纠结了很久. 问题是乘以一个交错的思想相结合. 不easy系列之(4)--考新郎 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 25941    Accepted Submission(s): 94…
http://acm.hdu.edu.cn/showproblem.php?pid=3521 题意 对于矩阵A,求e^A的值. 分析 这个定眼一看好像很熟悉,就是泰勒展开,可惜自己的高数已经还给老师了...比赛时不敢直接暴力写,实际上循环到一定次数,余式对结果的影响就相当小了.循环到50几次就可以了 #include<iostream> #include<cmath> #include<cstring> #include<queue> #include<…
不easy系列之(4)--考新郎 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 25425    Accepted Submission(s): 9311 Problem Description 国庆期间,省城HZ刚刚举行了一场盛大的集体婚礼,为了使婚礼进行的丰富一些,司仪暂时想出了有一个有意思的节目,叫做"考新郎",详细的…
http://acm.hdu.edu.cn/showproblem.php?pid=2123 Problem Description In this problem you need to make a multiply table of N * N ,just like the sample out. The element in the ith row and jth column should be the product(乘积) of i and j.   Input The first…
转载:http://www.klogk.com/posts/hdu4565/ 这里写的非常好,看看就知道了啊. 题意很easy.a,b,n都是正整数.求 Sn=⌈(a+b√)n⌉%m,(a−1)2<b<a2 这个题目也是2008年Google Codejam Round 1A的C题. 做法事实上很easy.记(a+b√)n为An,配项 Cn=An+Bn=(a+b√)n+(a−b√)n 两项恰好共轭,所以Cn是整数. 又依据限制条件 (a−1)2<b<a2⇒0<a−b√<…
Problem Description A sequence Sn is defined as:Where a, b, n, m are positive integers.┌x┐is the ceil of x. For example, ┌3.14┐=4. You are to calculate Sn. You, a top coder, say: So easy!  Input There are several test cases, each test case in one lin…
http://acm.hdu.edu.cn/showproblem.php?pid=4565 首先知道里面那个东西,是肯定有小数的,就是说小数部分是约不走的,(因为b限定了不是一个完全平方数). 因为(a - 1)^2 < b < (a ^ 2),所以其不是完全平方数,假如是,那么设其为c,则有a - 1 < c < a,这是矛盾的 所以,向上取整这个步骤,是必不可少的了. 那么,我在它后面加上一个< 1的数,同时使得它们结合成为整数,那就相当于帮它取整了.根据二项式定理 (…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=4565 题目大意: 给出a,b,n,m,求出的值, 解题思路: 因为题目中出现了开根号,和向上取整后求余,所以用矩阵快速幂加速求解过程的时候,会产生误差,就很自然地想到了凑数,因为(a-1)^2<b<a^2,得出0<a-sqrt(b)<1,则无论n取多大,(a-sqrt(b))^n都是小于1的,(a-sqrt(b))^n 与 (a+sqrt(b))^n共轭,两者展开后会相互抵销,所以(…