346. Moving Average from Data Stream】的更多相关文章

/* * 346. Moving Average from Data Stream * 2016-7-11 by Mingyang * 这里注意的就是(double) sum / count * sum需要转换成double才能继续往下除,因为不转的话最后不能成为整数14除以3等于4 */ class MovingAverage { public Queue<Integer> queue; public int sum = 0; public int si; public int count…
Given a stream of integers and a window size, calculate the moving average of all integers in the sliding window. For example, MovingAverage m = new MovingAverage(3); m.next(1) = 1 m.next(10) = (1 + 10) / 2 m.next(3) = (1 + 10 + 3) / 3 m.next(5) = (1…
Given a stream of integers and a window size, calculate the moving average of all integers in the sliding window. For example, MovingAverage m = new MovingAverage(3); m.next(1) = 1 m.next(10) = (1 + 10) / 2 m.next(3) = (1 + 10 + 3) / 3 m.next(5) = (1…
[抄题]: Given a stream of integers and a window size, calculate the moving average of all integers in the sliding window. For example, MovingAverage m = new MovingAverage(3); m.next(1) = 1 m.next(10) = (1 + 10) / 2 m.next(3) = (1 + 10 + 3) / 3 m.next(5…
Given a stream of integers and a window size, calculate the moving average of all integers in the sliding window. For example,MovingAverage m = new MovingAverage(3);m.next(1) = 1m.next(10) = (1 + 10) / 2m.next(3) = (1 + 10 + 3) / 3m.next(5) = (10 + 3…
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 队列 日期 题目地址:https://leetcode-cn.com/problems/moving-average-from-data-stream/ 题目描述 Given a stream of integers and a window size, calculate the moving average of all integers in t…
Given a stream of integers and a window size, calculate the moving average of all integers in the sliding window. For example,MovingAverage m = new MovingAverage(3);m.next(1) = 1m.next(10) = (1 + 10) / 2m.next(3) = (1 + 10 + 3) / 3m.next(5) = (10 + 3…
原题链接在这里:https://leetcode.com/problems/moving-average-from-data-stream/ 题目: Given a stream of integers and a window size, calculate the moving average of all integers in the sliding window. For example, MovingAverage m = new MovingAverage(3); m.next(1…
Given a stream of integers and a window size, calculate the moving average of all integers in the sliding window. For example, MovingAverage m = new MovingAverage(3); m.next(1) = 1 m.next(10) = (1 + 10) / 2 m.next(3) = (1 + 10 + 3) / 3 m.next(5) = (1…
Given a stream of integers and a window size, calculate the moving average of all integers in the sliding window. For example, MovingAverage m = new MovingAverage(3); m.next(1) = 1 m.next(10) = (1 + 10) / 2 m.next(3) = (1 + 10 + 3) / 3 m.next(5) = (1…
Given a stream of integers and a window size, calculate the moving average of all integers in the sliding window. For example,MovingAverage m = new MovingAverage(3);m.next(1) = 1m.next(10) = (1 + 10) / 2m.next(3) = (1 + 10 + 3) / 3m.next(5) = (10 + 3…
Given a stream of integers and a window size, calculate the moving average of all integers in the sliding window. For example,MovingAverage m = new MovingAverage(3);m.next(1) = 1m.next(10) = (1 + 10) / 2m.next(3) = (1 + 10 + 3) / 3m.next(5) = (10 + 3…
[抄题]: 给出一串整数流和窗口大小,计算滑动窗口中所有整数的平均值. MovingAverage m = new MovingAverage(3); m.next(1) = 1 // 返回 1.00000 m.next(10) = (1 + 10) / 2 // 返回 5.50000 m.next(3) = (1 + 10 + 3) / 3 // 返回 4.66667 m.next(5) = (10 + 3 + 5) / 3 // 返回 6.00000 [暴力解法]: 来一个数就存数组,for…
Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…
Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 Design a d…
常规方法 超时 class MedianFinder { vector<int> coll; public: MedianFinder(){ } void heapfu(vector<int>& coll,int idx,int max){ int left=2*idx+1,right=2*idx+2; int largest=idx; if(left<max&&coll[left]>coll[idx]) largest=left; if(rig…
题目如下:(https://leetcode.com/problems/find-median-from-data-stream/) Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] …
Find Median from Data Stream Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is…
Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 Design a d…
Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…
题目: Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 Design…
https://leetcode.com/problems/data-stream-as-disjoint-intervals/ Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the da…
问题描述: Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. 解题思路: 这道题是目前最新的题,其实思路很容易找到,难点在于考虑到所有的可能的情形. 首先要确定类必须有一个保存当前结果的集合类List<Interval>,其元素的按Interval的起始值的大小排序,…
https://leetcode.com/problems/find-median-from-data-stream/ Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the m…
LintCode 81. Data Stream Median (Hard) 思路: 用一个大根堆保存较小的一半数, 一个小根堆保存较大的一半数. 每次根据num和两个堆顶的数据决定往哪个堆里面放. 放完后进行平衡确保两个堆的size差不超过1. 利用两个堆的size和堆顶值计算median. 大根堆可以表示为priority_queue<int, vector<int>, less<int>>, 其实priority_queue<int>默认就是大根堆.…
Plz take my miserable life T T. 和57 insert interval一样的,只不过insert好多. 可以直接用57的做法一个一个加,然后如果数据大的话,要用tree map,可以迅速找到切入点. Key用的左边界. /** * Definition for an interval. * public class Interval { * int start; * int end; * Interval() { start = 0; end = 0; } * I…
原来国外有个源码(TechnicalAnalysisEngine src 1.25)内部对EMA的计算是: var copyInputValues = input.ToList(); for (int i = period; i < copyInputValues.Count; i++) { var resultValue = (copyInputValues[i] - returnValues.Last()) * multiplier + returnValues.Last(); return…
Question Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 D…
Data Stream Median Numbers keep coming, return the median of numbers at every time a new number added. Have you met this question in a real interview? Example For numbers coming list: [1, 2, 3, 4, 5], return [1, 1, 2, 2, 3]. For numbers coming list:…
git clone时出现 error:inflate:data stream error(incorrect data check) fatal:serrious inflate inconsistency fatal:index-pack failed 经了解,此问题是遗留问题,之前是因为公司对gitlab服务器进行数据迁移而引起这种git clone失败的原因,现象非常奇怪,大部分project是可以clone的,小部分不行,有一些人clone没问题的,有些人就是不行,我被这个问题困扰了好久…