题目链接:http://codeforces.com/contest/450/problem/C 题目意思:给出一个 n * m 大小的chocolate bar,你需要在这个bar上切 k 刀,使得最小的部分面积尽可能大,求出这个被划分后的最小部分面积最大可以为多少.如果这个chocolate bar 不能切成 k 部分,则输出-1.注意,每一刀需要符合3个条件:1.打横切或者打竖切: 2.每一刀只能经过unit square(即1*1的单元bar)的边,也就是说不能把一个单元bar损坏,要完…
C. Jzzhu and Chocolate time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Jzzhu has a big rectangular chocolate bar that consists of n × m unit squares. He wants to cut this bar exactly k time…
C. Jzzhu and Chocolate time limit per test: 1 seconds memory limit per test: 256 megabytes input: standard input output: standard output Jzzhu has a big rectangular chocolate bar that consists of \(n × m\) unit squares. He wants to cut this bar exact…
CodeForces 450B Jzzhu and Sequences (矩阵优化) Description Jzzhu has invented a kind of sequences, they meet the following property: \[f_1=x\] \[f_2=y\] \[f_i=f_{i-1}+f_{i+1}\text {(i>2)}\] You are given x and y, please calculate fn modulo 1000000007 (10…
Jzzhu and Chocolate time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Jzzhu has a big rectangular chocolate bar that consists of n × m unit squares. He wants to cut this bar exactly k times.…
题目描述: Jzzhu and Cities time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Jzzhu is the president of country A. There are n cities numbered from 1 to n in his country. City 1 is the capital of…
//area=(n*m)/ ((x+1)*(k-x+1)) //1: x==0; //2: x=n-1 //3: x=m-1 # include <stdio.h> long long max(long long x,long long y) { return x>y? x:y; } int main() { long long n,m,k,sum,t,ans; scanf("%lld%lld%lld",&n,&m,&k); sum=n+m-2…
