变形课 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/65536 K (Java/Others) Total Submission(s): 18474 Accepted Submission(s): 6663 Problem Description 呃--变形课上Harry碰到了一点小麻烦,因为他并不像Hermione那样能够记住所有的咒语而随意的将一个棒球变成刺猬什么的,但是他发现了变形咒语的一个统一规律:如果咒语是以a…

Description An abandoned country has n(n≤100000) villages which are numbered from 1 to n. Since abandoned for a long time, the roads need to be re-built. There are m(m≤1000000) roads to be re-built, the length of each road is wi(wi≤1000000). Guarante…

POJ 2676 Sudoku Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 17627   Accepted: 8538   Special Judge Description Sudoku is a very simple task. A square table with 9 rows and 9 columns is divided to 9 smaller squares 3x3 as shown on the…

Curling 2.0 Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 30   Accepted Submission(s) : 16 Problem Description On Planet MM-21, after their Olympic games this year, curling is getting popular.…

题目分析: 对于A,B,C,D四支队伍,两两之间进行一场比赛,获胜得3分,平局得1分,失败不得分,现在对给出的四个队伍的得分,判断能否满足得到这种分数,且方案唯一输出yes,不唯一输出no,不可能则输出worng,由于一共只有6场比赛,直接通过暴力每一种可能,创建mat[i][j]存放队伍i和队伍j比赛对于i来说的得分,mat[j][i]存放对于j来说的得分,然后建立cal(int row,int col)深搜函数,对于每个mat[row][col]的结果都进行递归,查询得分为3,1,0的三种情…

 Stamps  The government of Nova Mareterrania requires that various legal documents have stamps attached to them so that the government can derive revenue from them. In terms of recent legislation, each class of document is limited in the number of st…

A Knight's Journey Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 66   Accepted Submission(s) : 27 Problem Description Background The knight is getting bored of seeing the same black and white…

题目 In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a mi…

深搜,从一点向各处搜找到全部能走的地方. Problem Description There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on…

/* (⊙v⊙)嗯 貌似是一个建图 拓扑+深搜的过程.至于为什么要深搜嘛..一个月前敲得题现在全部推了重敲,于是明白了.因为题意要求如果有多个可能的解的话. * 就要输出字典序最小的那个.所以可以对26个英文字母从小到大尝试能否排出结果.于是出现了 深搜回溯.先选定入度为0的边框.标记为已用.将所有与它连通的 * 边框入度减一.然后递归搜索下一个.此时开始回溯.当前边框标记为未用,所有与它连通的边框入度加1. * 建图的过程则是.对每一个字母的边框测量出来.然后对A里的其它字母B.(B 覆盖 A…