Hamming Distance Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 499    Accepted Submission(s): 163 Problem Description (From wikipedia) For binary strings a and b the Hamming distance is equal…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4712 解题报告:输入n个数,用十六进制的方式输入的,任意选择其中的两个数进行异或,求异或后的数用二进制表示后1的个数最小的是多少?(n<=100000) 这题看了解题报告,大家都说用随机算法,试过了,随机100000次就过了,50000次都不行,但还是不懂这样怎么可以,唯一的解释就是这个值域也就是结果一共只有21个, 得出正确的结果的可能性很大,但是并不能100%保证结果是对的.无语第一次碰见这种算…

http://acm.hdu.edu.cn/showproblem.php?pid=4712 题意:计算任意两个十六进制的数异或后1的最少个数. 思路:用随机数随机产生两个数作为下标,记录这两个数异或后1的个数,输出1的个数最少是多少. #include <stdio.h> #include <algorithm> #include <time.h> #include <math.h> using namespace std; ; <<; int…

Hamming Distance Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others) Problem Description (From wikipedia) For binary strings a and b the Hamming distance is equal to the number of ones in a XOR b. For calculating Hammi…

Hamming Distance Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 1569    Accepted Submission(s): 616 Problem Description (From wikipedia) For binary strings a and b the Hamming distance is equal…

http://acm.hdu.edu.cn/showproblem.php?pid=4712 Hamming Distance Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 1610    Accepted Submission(s): 630 Problem Description (From wikipedia) For bina…

Hamming Distance Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 1051 Accepted Submission(s): 396 Problem Description (From wikipedia) For binary strings a and b the Hamming distance is equal to t…

Hamming Distance Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 1845    Accepted Submission(s): 740 Problem Description (From wikipedia) For binary strings a and b the Hamming distance is equa…

仔细阅读ORB的代码,发现有很多细节不是很明白,其中就有用暴力方式测试Keypoints的距离,用的是HammingLUT,上网查了才知道,hamming距离是相差位数.这样就好理解了. 我理解的HammingLUT lut; result=lut((a),(b),size_t size):result=a与b的hamming distance+size; unsigned int hamdist(unsigned int x, unsigned int y) { unsigned int di…

http://acm.hdu.edu.cn/showproblem.php?pid=4712 Hamming Distance Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 797    Accepted Submission(s): 284 Problem Description (From wikipedia) For binary…