大致题意: 从n个盒子里面取出s多花.每一个盒子里面的花都同样,而且每一个盒子里面花的多数为f[i],求取法总数. 解题思路: 我们知道假设n个盒子里面花的数量无限,那么取法总数为:C(s+n-1, n-1) = C(s+n-1, s). 能够将问题抽象成:x1+x2+...+xn = s, 当中0<=xi <= f[i].求满足条件的解的个数. 两种方法能够解决问题: 方法一:这个问题的解能够等价于:mul = (1+x+x^2+...+x^f[1])*(1+x+x^2+...+x^f[2]…

E. Devu and Flowers 题目连接: http://codeforces.com/contest/451/problem/E Description Devu wants to decorate his garden with flowers. He has purchased n boxes, where the i-th box contains fi flowers. All flowers in a single box are of the same color (hen…

题意:n<20个箱子,每个里面有fi朵颜色相同的花,不同箱子里的花颜色不同,要求取出s朵花,问方案数 题解:假设不考虑箱子的数量限制,隔板法可得方案数是c(s+n-1,n-1),当某个箱子里的数量超过fi时,方案数是c(s-f[i]-1+n-1,n-1),容斥原理求,状压枚举哪几个箱子超过了f[i],答案就是超过0个-超过1个+超过2个... 由于c(n,m)的m很小,直接暴力求解 //#pragma GCC optimize(2) //#pragma GCC optimize(3) //#pr…

Codeforces Round #258 (Div. 2)[ABCD] ACM 题目地址:Codeforces Round #258 (Div. 2) A - Game With Sticks 题意:  Akshat and Malvika两人玩一个游戏,横竖n,m根木棒排成#型,每次取走一个交点,交点相关的横竖两条木棒要去掉,Akshat先手,给出n,m问谁赢. 分析:  水题,非常明显无论拿掉哪个点剩下的都是(n-1,m-1),最后状态是(0,x)或(x,0),也就是拿了min(n,m)-…

A. Game With Sticks (451A) 水题一道,事实上无论你选取哪一个交叉点,结果都是行数列数都减一,那如今就是谁先减到行.列有一个为0,那么谁就赢了.因为Akshat先选,因此假设行列中最小的一个为奇数,那么Akshat赢,否则Malvika赢. 代码: #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace…

题目链接:Codeforces 451E Devu and Flowers 题目大意:有n个花坛.要选s支花,每一个花坛有f[i]支花.同一个花坛的花颜色同样,不同花坛的花颜色不同,问说能够有多少种组合. 解题思路:2n的状态,枚举说那些花坛的花取超过了,剩下的用C(n−1sum+n−1)隔板法计算个数.注意奇数的位置要用减的.偶数的位置用加的.容斥原理. #include <cstdio> #include <cstring> #include <cmath> #in…

题目链接: http://codeforces.com/problemset/problem/451/E E. Devu and Flowers time limit per test4 secondsmemory limit per test256 megabytes 问题描述 Devu wants to decorate his garden with flowers. He has purchased n boxes, where the i-th box contains fi flow…

A - Game With Sticks 题目的意思: n个水平条,m个竖直条,组成网格,每次删除交点所在的行和列,两个人轮流删除,直到最后没有交点为止,最后不能再删除的人将输掉 解题思路: 每次删除交点所在的行和列,则剩下n-1行和m-1列,直到行或列被删完为止,最多删除的次数为min(n,m),删除min(n,m)后剩余的都是行或者列(注意行与行,列与列之间不可能有交点).只需要判断min(n,m)的奇偶性. #include <iostream> #include <vector&…

http://blog.csdn.net/rowanhaoa/article/details/38116713 A:Game With Sticks 水题.. . 每次操作,都会拿走一个横行,一个竖行. 所以一共会操作min(横行,竖行)次. #include<stdio.h> #include<iostream> #include<stdlib.h> #include<string.h> #include<algorithm> #include…

Codeforces Round #258 (Div. 2) Devu and Flowers E. Devu and Flowers time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output Devu wants to decorate his garden with flowers. He has purchased n boxes…

Codeforces #344 Div.2 Interview 题目描述:求两个序列的子序列或操作的和的最大值 solution 签到题 时间复杂度:\(O(n^2)\) Print Check 题目描述:有一个棋盘,对其进行染色,每次染一行或一列,后来的颜色会覆盖原来的颜色,输出最后的棋盘. solution 题解用二维线段树,其实可以不用. 对染色进行离线操作,那么染过的格子.行.列就不用再染了.所以每个格子可以记录四个指针,分别是行前驱,行后继,列前驱列后继,染色时按照这个跳着来染就好了.…

Codeforces #345 Div.1 打CF有助于提高做题的正确率. Watchmen 题目描述:求欧拉距离等于曼哈顿距离的点对个数. solution 签到题,其实就是求有多少对点在同一行或同一列. 时间复杂度:\(O(nlogn)\) Image Preview 题目描述:给定看一张照片的时间,翻页的时间,把图片翻转的时间.一开始屏幕显示第一张照片,可以向左或向右翻,不能跳过还没有看过的图片,方向不对的图片要先翻转再看,看过的不消耗翻转时间与看照片时间,问在一定时间内,最多能看多少张照…

E. Devu and Flowers time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output Devu wants to decorate his garden with flowers. He has purchased n boxes, where the i-th box contains fi flowers. All fl…

Codeforces Beta Round #27 (Codeforces format, Div. 2) http://codeforces.com/contest/27 A #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define maxn 1000005 typ…

CF451E Devu and Flowers 题意: \(Devu\)有\(N\)个盒子,第\(i\)个盒子中有\(c_i\)枝花.同一个盒子内的花颜色相同,不同盒子的花颜色不同.\(Devu\)要从中选出\(M\)枝花,求有多少种方案,对\(10e9+7\)取模. 数据范围 \(1 \le N \le 20,0 \le M \le 10^{14},0 \le c_i \le 10^{12}\) 其实就是求多重集组合数的模板题. 可以看看我写的博客 一些注意点,发现直接求会爆\(long lo…

CF451E Devu and Flowers(容斥) 题目大意 \(n\)种花每种\(f_i\)个,求选出\(s\)朵花的方案.不一定每种花都要选到. \(n\le 20\) 解法 利用可重组合的公式. 不考虑\(f_i\)的限制,直接可重组合的方案是,意思是从可以重复的\(n\)个元素中取出\(r\)个的个数.注意,根据定义,此时\(r\)种每个都要选. \[ f(s,r)={s+r-1 \choose r-1} \] 考虑限制怎么办,我们先容斥. 我们可以钦定某些花选择了\(f_i+1\)…

Codeforces#441 Div.2 四小题 链接 A. Trip For Meal 小熊维尼喜欢吃蜂蜜.他每天要在朋友家享用N次蜂蜜 , 朋友A到B家的距离是 a ,A到C家的距离是b ,B到C家的距离是c  (A- >Rabbit   B- >Owl    C ->Eeyore),他不能连续两顿饭都在同一位朋友家里蹭 他现在位于A的家里, 请问他一天最少要跑多少路. 当然是要找一条最短的路折返跑了啊,是不是很简单. #include<bits/stdc++.h> us…

codeforces #592(Div.2) A Pens and Pencils Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them. While preparing for th…

codeforces #578(Div.2) A. Hotelier Amugae has a hotel consisting of 1010 rooms. The rooms are numbered from 00 to 99 from left to right. The hotel has two entrances - one from the left end, and another from the right end. When a customer arrives to t…

codeforces #577(Div.2) A  Important Exam A class of students wrote a multiple-choice test. There are nn students in the class. The test had mm questions, each of them had 55 possible answers (A, B, C, D or E). There is exactly one correct answer for…

Zap FGD正在破解一段密码,他需要回答很多类似的问题:对于给定的整数a,b和d,有多少正整数对x,y,满足x<=a,y<=b,并且gcd(x,y)=d.作为FGD的同学,FGD希望得到你的帮助. Input 第一行包含一个正整数n,表示一共有n组询问.(1<=n<= 50000)接下来n行,每行表示一个询问,每行三个 正整数,分别为a,b,d.(1<=d<=a,b<=50000) Output 对于每组询问,输出到输出文件zap.out一个正整数,表示满足条件…

http://codeforces.com/contest/599/problem/D 题意:给出总的方格数x,问有多少种不同尺寸的矩形满足题意,输出方案数和长宽(3,5和5,3算两种) 思路:比赛的时候gg了..其实稍微在纸上推一下.就会得到对于n,m的矩形,一共会有-n*n*n+3*n*n*m+n+3*n*m的方格.数量级是n3. 我们可以实际跑一遍.发现对于x1E18的数量级,n不会超过1442550,1E6,可以搞. 需要注意的是,一个是会爆int,所以记得用long long 另一个是…

这题又是容斥原理,最近各种做容斥原理啊.当然,好像题解给的不是容斥原理的方法,而是用到Lucas定理好像.这里只讲容斥的做法. 题意:从n个容器中总共取s朵花出来,问有多少种情况.其中告诉你每个盒子中有多少朵花. 分析:其实就是求方程: x1+x2+...+xn = s 的整数解的个数,方程满足: 0<=x1<=a[1], 0<=x2<=a[2]... 设:A1 = {x1 >= a[1]+1} , A2 = {x2 >= a[2]+1} , .... , An = {…

题目链接:http://codeforces.com/problemset/problem/459/B 题意: 给出n支花,每支花都有一个漂亮值.挑选最大和最小漂亮值得两支花,问他们的差值为多少,并且有多少种选法(无先后顺序). 现场做时,想到的是:用multimap记录每个漂亮值出现的次数,并不断更新最大最小值. 这个方法很笨,而且multimap的val值是多余的. 需要注意特殊情况:max==min 代码如下: #include<iostream>//A - Pashmak and Fl…

Discription Devu wants to decorate his garden with flowers. He has purchased n boxes, where the i-th box contains fi flowers. All flowers in a single box are of the same color (hence they are indistinguishable). Also, no two boxes have flowers of the…

B. Alyona and flowers Problem Description: Let's define a subarray as a segment of consecutive flowers. The mother suggested some set of subarrays. Alyona wants to choose several of the subarrays suggested by her mother. After that, each of the flowe…

链接:http://codeforces.com/contest/322/problem/B 这题做错了.没考虑周全. #include <cstdio> #include <cstdlib> #include <iostream> #include <algorithm> using namespace std; int main(void) { int r, g, b; while (~scanf("%d%d%d", &r,…

题目链接:http://codeforces.com/contest/451/problem/B 思路:首先找下降段的个数,假设下降段是大于等于2的,那么就直接输出no,假设下降段的个数为1,那么就把下降段的起始位置和结束位置记录下来然后进行推断,在进行推断时,有几种特殊情况:(s表示起始位置,e表示结束位置) 1.当e==n&&s!=1时,满足a[n]>a[s-1]输出yes: 2当s==1&&==n时,满足a[1]<a[e+1] 输出yes: 3当s==1&…

D. Count Good Substrings 题目连接: http://codeforces.com/contest/451/problem/D Description We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after…

C. Predict Outcome of the Game 题目连接: http://codeforces.com/contest/451/problem/C Description There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but…