Feel Good   Description Bill is developing a new mathematical theory for human emotions. His recent investigations are dedicated to studying how good or bad days influent people's memories about some period of life. A new idea Bill has recently devel…

Feel Good Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 16786   Accepted: 4627 Case Time Limit: 1000MS   Special Judge Description Bill is developing a new mathematical theory for human emotions. His recent investigations are dedicated…

Description The main land of Japan called Honshu is an island surrounded by the sea. In such an island, it is natural to ask a question: “Where is the most distant point from the sea?” The answer to this question for Honshu was found in 1996. The mos…

1619 - Feel Good Time limit: 3.000 seconds   Bill is developing a new mathematical theory for human emotions. His recent investigations are dedi- cated to studying how good or bad days in uent people's memories about some period of life. A new idea B…

Feel Good Time Limit: 3000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu Bill is developing a new mathematical theory for human emotions. His recent investigations are dedicated to studying how good or bad days influent people's memories a…

题目: 思路: 预处理出a[i]在哪个范围区间内是最小的,然后直接遍历a数组求答案就可以了. 这个预处理的技巧巧妙的用了之前的处理结果.(大佬tql) 代码: #include <bits/stdc++.h> #define inf 0x3f3f3f3f #define MAX 1e3 #define FRE() freopen("in.txt","r",stdin) #define FRO() freopen("out.txt",&…

Bill is developing a new mathematical theory for human emotions. His recent investigations are dedicated to studying how good or bad days influent people's memories about some period of life. A new idea Bill has recently developed assigns a non-negat…

题意:给你许多串字符串,从中提取电话号码,输出出现复数次的电话号码及次数. 以下是我艰难的AC历程:(这题估计是我刷的题目题解次数排前的了...) 题目不是很难理解,刚开始想到用map,但stl的map不是很放心,怕超时.于是放心的用数组敲了.(事实证明我放心过头了) 刚开始在Vjugde里面提交老SE,我还以为uva又挂了,最近各种挂啊... 后来又刷了一题过来提交,还是SE.某大神说这题uva完全挂了,没人能提交得了,只能去poj交,于是屁颠屁颠跑poj给TLE了. 在敲的时候就考虑到用ge…

题目链接:http://poj.org/problem?id=2796 单调栈可以O(n)得到以每个位置为最小值,向左右最多扩展到哪里. #include<cstdio> #include<algorithm> #include<stack> using namespace std; ; int a[maxn]; int l[maxn]; int r[maxn]; long long pre[maxn]; stack< pair<int,int> &g…

中文题 (一般都比较坑) 思路:DFS (感谢学长的幻灯片) 这破题把我折腾惨了!!!搞了n天 // by Sirius_Ren #include <cstdio> #include <cstring> #include <algorithm> using namespace std; int n,a[100],sum,jy,maxx,q; bool vis[100]; bool cmp(int a,int b){return a>b;} bool dfs(int…