Description ``Accordian'' Patience You are to simulate the playing of games of ``Accordian'' patience, the rules for which are as follows: Deal cards one by one in a row from left to right, not overlapping. Whenever the card matches its immediate n…
水题.. 求任意时刻时针和分针的夹角,其结果在0°到180°之间. 这里又一次用到了sscanf()函数,确实很方便. 思路:我们分别求出时针和分针转过的角度,然后大的减小的,如果结果ans大于180,那么ans = 360 - ans. ClockHands The medieval interest in mechanical contrivances is well illustrated by the development of the mechanical clock, the…