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Description There are n piles of stones of sizes a1, a2, -, an lying on the table in front of you. During one move you can take one pile and add it to the other. As you add pile i to pile j, the size of pile j increases by the current size of pile i,…
A. Where do I Turn? 叉积判断. B. Effective Approach 记录位置. C. Flying Saucer Segments 假设有\(n\)个人,那么\(1\)要移动的话,需要先移动前\(n-1\)个人. 有点类似于汉诺塔问题,写出递推式后矩阵+快速幂计算. D. Naughty Stone Piles \(k\)叉树,权值越小的深度越大,每种\(k\)做一次即可. E. Anniversary Fibonacci数列性质\[gcd(F_a, F_b)=F_{…
Stone Game 题目链接 题目描述 Alice and Bob are always playing game! The game today is about taking out stone from the stone piles in turn. There are n piles of stones, and the i-th pile contains A[i] stones. As the number of stones in each pile differs from…
题目描述 Alice and Bob are always playing game! The game today is about taking out stone from the stone piles in turn.There are n piles of stones, and the i-th pile contains A[i] stones.As the number of stones in each pile differs from its neighbor’s, th…
A New Stone Game Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 5769   Accepted: 3158 Description Alice and Bob decide to play a new stone game.At the beginning of the game they pick n(1<=n<=10) piles of stones in a line. Alice and Bob…
Zhuge Liang's Stone Sentinel Maze Time Limit: 10000/4000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 385    Accepted Submission(s): 106 Problem Description Zhuge Liang was a chancellor of the state of Shu Han dur…
A New Stone Game Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 5453   Accepted: 2989 Description Alice and Bob decide to play a new stone game.At the beginning of the game they pick n(1<=n<=10) piles of stones in a line. Alice and Bob…
F - Again Stone Game Time Limit:2000MS     Memory Limit:32768KB     64bit IO Format:%lld & %llu Submit Status Description Alice and Bob are playing a stone game. Initially there are n piles of stones and each pile contains some stone. Alice stars the…
http://poj.org/problem?id=1740 题目大意就是,对于n堆石子,每堆若干个,两人轮流操作,每次操作分两步,第一步从某堆中去掉至少一个,第二步(可省略)把该堆剩余石子的一部分分给其它的某些堆.最后谁无子可取即输. 看了题解感觉太神了. 首先我们来分析: 当只有一堆时,先手必胜,直接一次取完即可 当有两堆时,分两种情况,一是两堆相同时,先手必输,因为无论先手怎样取,后手总有办法再次平衡两堆:而是两堆不同时,先手必胜,因为先手总有办法先平衡两堆,然后就像一的情况. 当有三堆时…
[题目] Description The funny stone game is coming. There are n piles of stones, numbered with 0, 1, 2, ..., n − 1. Twopersons pick stones in turn. In every turn, each person selects three piles of stones numbered i, j, k(i < j, j ≤ k and at least one s…