题意:有n个点,问其中某一对点的距离最小是多少 分析:分治法解决问题:先按照x坐标排序,求解(left, mid)和(mid+1, right)范围的最小值,然后类似区间合并,分离mid左右的点也求最小值 POJ 3714 #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> const int N = 1e5 + 5; const double INF = 1e…

题目:  http://poj.org/problem?id=3714 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=27048#problem/D Raid Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 7355   Accepted: 2185 Description After successive failures in the battles aga…

Description After successive failures in the battles against the Union, the Empire retreated to its last stronghold. Depending on its powerful defense system, the Empire repelled the six waves of Union's attack. After several sleepless nights of thin…

Raid Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 7473   Accepted: 2221 Description After successive failures in the battles against the Union, the Empire retreated to its last stronghold. Depending on its powerful defense system, the…

Description After successive failures in the battles against the Union, the Empire retreated to its last stronghold. Depending on its powerful defense system, the Empire repelled the six waves of Union's attack. After several sleepless nights of thin…

版权声明:本文作者靖心,靖空间地址:http://blog.csdn.net/kenden23/.未经本作者同意不得转载. https://blog.csdn.net/kenden23/article/details/36407517 本题是一般近期对点求解.略微添加点限定:有两个集合点,要求不同集合中的点的近期对. 那么就添加一个推断.假设是同一个集合中的点,那么就返回最大值.其它和一般的近期对点解法一样. 注意:本题数据有重合点.那么就要防止分类的时候溢出. Geeks上的近期对的程序是无法…

解题思路: 分治法求平面近期点对.点分成两部分,加个标记就好了. #include <iostream> #include <cstring> #include <cstdlib> #include <cstdio> #include <cmath> #include <vector> #include <queue> #include <algorithm> #include <iomanip>…

这个讲的好: https://phoenixzhao.github.io/%E6%B1%82%E6%9C%80%E8%BF%91%E5%AF%B9%E7%9A%84%E4%B8%89%E7%A7%8D%E6%96%B9%E6%B3%95/ 分治法 先空着 看一下这个第三个方法(随机增量哈希,O(n)) 1.千万不要用unordered_map/hash_map!T飞是肯定的:要手写哈希表,所以码量就很大:手写哈希表方法记一下 2.事实上以d为边长画格子,每次遍历相邻的9个格子,常数要比以d/2边…

[题目链接] http://poj.org/problem?id=3714 [算法] 分治求平面最近点对 [代码] #include <algorithm> #include <bitset> #include <cctype> #include <cerrno> #include <clocale> #include <cmath> #include <complex> #include <cstdio> #…

[题目链接]:http://poj.org/problem?id=3714 [题意] 给你两类的点; 各n个; 然后让你求出2*n个点中的最近点对的距离; 这里的距离定义为不同类型的点之间的距离; [题解] 分治法; 不断划分小区间; 求出小区间内的最小值; 为后面的大区间剪枝; 只是要求点的类型不同才能剪枝了; [Number Of WA] 0 [完整代码] #include <iostream> #include <cstdio> #include <iomanip>…