HDU 3999 二叉排序树】的更多相关文章

The order of a Tree Problem Description The shape of a binary search tree is greatly related to the order of keys we insert. To be precisely:1.  insert a key k to a empty tree, then the tree become a tree with only one node;2.  insert a key k to a no…
/****************************************************************** 题目: The order of a Tree(hdu 3999) 链接: http://acm.hdu.edu.cn/showproblem.php?pid=3999 题意: 给你一个序列建立一棵二叉搜索树 要你找出另外一个序 列,可以建立和原序列建立的二叉搜索树一样且这个序列 是字典序最小 算法: 二叉搜索树 思想: 对于一个二叉搜索树,它的先序遍历是能建立…
这里是杭电hdu上的链接:http://acm.hdu.edu.cn/showproblem.php?pid=3999  Problem Description: As we know,the shape of a binary search tree is greatly related to the order of keys we insert. To be precisely: 1.  insert a key k to a empty tree, then the tree becom…
The order of a Tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 845    Accepted Submission(s): 461 Problem Description As we know,the shape of a binary search tree is greatly related to the…
建一个二叉搜索树,然后前序输出. 用链表建的,发现很久没做都快忘了... #include <cstdio> #include <cstdlib> struct Node{ int v; Node* l; Node* r; }; Node* root; Node* newnd(int value) { Node* u = (Node*) malloc(sizeof(Node)); if (u != NULL) { u -> v = value; u -> r = u -…
The order of a Tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 835    Accepted Submission(s): 453 Problem Description As we know,the shape of a binary search tree is greatly related to the…
The order of a Tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 917    Accepted Submission(s): 496 Problem Description As we know,the shape of a binary search tree is greatly related to the…
Elven Postman Time Limit: 1500/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 591    Accepted Submission(s): 329 Problem Description Elves are very peculiar creatures. As we all know, they can live for a very…
HDU 5444 题意:给你一棵树的先序遍历,中序遍历默认是1...n,然后q个查询,问根节点到该点的路径(题意挺难懂,还是我太傻逼) 思路:这他妈又是个大水题,可是我还是太傻逼.1000个点的树,居然用标准二叉树结构来存点,,,卧槽想些什么东西.可以用一维数组,left,right直接指向位置就行了,我这里用的是链表.对于读入的序列,生成一个二叉排序树,同时记录一下路径就可以了,后面居然忘了清空path又wa了一发. #include<iostream> #include<cstdio…
HDU 模拟题, 枚举1002 1004 1013 1015 1017 1020 1022 1029 1031 1033 1034 1035 1036 1037 1039 1042 1047 1048 1049 1050 1057 1062 1063 1064 1070 1073 1075 1082 1083 1084 1088 1106 1107 1113 1117 1119 1128 1129 1144 1148 1157 1161 1170 1172 1177 1197 1200 1201…