解决:JavaScript 在函数中使用Ajax获取的值作为函数的返回值,结果无法获取到返回值 原因:ajax默认使用异步方式,要将异步改为同步方式 案例:通过区域ID,获取该区域下所有的学校 var School = new Object(); //保存区下面所有学校 School.GetAllInArea = function (areaId) { var returnData; $.ajax({ url: "/Area/Home/Schools/" + areaId, type:…
通过JS获取星座的函数 function getConstellation(m,d){ var s="魔羯水瓶双鱼牡羊金牛双子巨蟹狮子处女天秤天蝎射手魔羯"; var arr=[20,19,21,21,21,22,23,23,23,23,22,22]; return s.substr(m*2-(d<arr[m-1]?2:0),2); }…
用一个实际代码来说明. class A { public: staticvoid staticmember(){cout<<"static"<<endl;} //static member void nonstatic(){cout<<"nonstatic"<<endl;} //nonstatic member virtualvoid virtualmember(){cout<<&qu…
linux的man页中对gettimeofday函数的说明中,有这样一个说明: $ man gettimeofday DESCRIPTION The functions gettimeofday and settimeofday can get and set the time as well as a timezone. The tv argument is a timeval struct, as specified in <sys/time.h>: …