As Easy As A+B Problem Description These days, I am thinking about a question, how can I get a problem as easy as A+B? It is fairly difficulty to do such a thing. Of course, I got it after many waking nights.Give you some integers, your task is to so…

As Easy As A+B Problem Description These days, I am thinking about a question, how can I get a problem as easy as A+B? It is fairly difficulty to do such a thing. Of course, I got it after many waking nights. Give you some integers, your task is to s…

1040水题; These days, I am thinking about a question, how can I get a problem as easy as A+B? It is fairly difficulty to do such a thing. Of course, I got it after many waking nights.Give you some integers, your task is to sort these number ascending (…

A water problem 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5832 Description Two planets named Haha and Xixi in the universe and they were created with the universe beginning. There is 73 days in Xixi a year and 137 days in Haha a year. Now you k…

排序,水题因为最后如果一个学生最好的排名有一样的,输出的课程有个优先级A>C>M>E那么按这个优先级顺序进行排序每次排序前先求当前课程的排名然后再与目前最好的排名比较.更新 至于查询,建立id与索引的映射即可. #include <iostream> #include <algorithm> #include <cstdio> #include <cstring> #include <map> using namespace s…

水题,分组排序即可. #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> using namespace std; /* 太水水水... */ +; int cnt1,cnt2,cnt3,cnt4; struct Node{ int id; int tot; int vir; int tal; bool operator<(const Node t…

Barricade Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 1418    Accepted Submission(s): 417 Problem Description The empire is under attack again. The general of empire is planning to defend h…

题意:给定n个数,让你从小到大排序. 析:不说什么了. 代码如下: #include <cstdio> #include <iostream> #include <cstring> #include <algorithm> #include <cmath> using namespace std; const int maxn = 1000 + 5; int a[maxn]; int main(){ int T, n; cin >>…

题意:裸排序 思路:排序 #include<iostream> #include<stdio.h> #include<algorithm> using namespace std; ]; int main(){ int t,n,i; scanf("%d",&t); while(t--){ scanf("%d",&n); ;i<n;++i) scanf("%d",&a[i]); so…

As Easy As A+B Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 53368    Accepted Submission(s): 22939 Problem Description These days, I am thinking about a question, how can I get a problem as…