poj3268 Silver Cow Party(农场派对)】的更多相关文章

Silver Cow Party Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 15156   Accepted: 6843 Description One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbered 1..N is going to attend the big cow party to be held at farm #X (1 ≤ X…
题目链接:http://poj.org/problem?id=3268 Silver Cow Party Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 24527   Accepted: 11164 Description One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbered 1..N is going to attend the big co…
题目描述 原题来自:USACO 2007 Feb. Silver N(1≤N≤1000)N (1 \le N \le 1000)N(1≤N≤1000) 头牛要去参加一场在编号为 x(1≤x≤N)x(1 \le x \le N)x(1≤x≤N) 的牛的农场举行的派对.有 M(1≤M≤100000)M(1\le M \le 100000)M(1≤M≤100000) 条有向道路,每条路长 Ti(1≤Ti≤100)T_i(1 \le T_i \le 100)T​i​​(1≤T​i​​≤100):每头牛都…
Description One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbered 1..N is going to attend the big cow party to be held at farm #X (1 ≤ X ≤ N). A total of M (1 ≤ M ≤ 100,000) unidirectional (one-way roads connects pairs of farms; road i re…
题目链接: https://vjudge.net/problem/POJ-3268 题目大意: 有编号为1-N的牛,它们之间存在一些单向的路径.给定一头牛的编号X,其他牛要去拜访它并且拜访完之后要返回自己原来的位置,求所有牛从开始到回家的时间是多少? 思路: 所有牛都回到了家所花费的时间就是这些牛中花费时间的最大者,可以正向的Dijkstra求出从X到每个点的最短时间,然后一个骚操作:将所有边反向(swap(Map[i][j], Map[j][i])),再从x用dijkstra求出X到每个点的最…
https://vjudge.net/problem/POJ-3268 一开始floyd超时了.. 对正图定点求最短,对逆图定点求最短,得到任意点到定点的往返最短路. #include<iostream> #include<cstdio> #include<queue> #include<cstring> #include<algorithm> #include<cmath> #include<stack> #define…
One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbered 1..N is going to attend the big cow party to be held at farm #X (1 ≤ X ≤ N). A total of M (1 ≤ M≤ 100,000) unidirectional (one-way roads connects pairs of farms; road i requires Ti (1…
题目链接 http://poj.org/problem?id=3268 题意 有向图中有n个结点,编号1~n,输入终点编号x,求其他结点到x结点来回最短路长度的最大值. 思路 最短路问题,有1000个结点,Floyd算法应该会超时,我刚开始使用的Dijkstra算法也超时,原因是因为我使用一个循环遍历结点1~n,每次遍历我都使用两次Dijkstra求i到x和x到i的最短路,时间复杂度太高.降低时间复杂度的方法是先在原矩阵的基础上使用dijkstra求结点x到其余各点的最短路径,然后将矩阵转置,在…
One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbered 1..N is going to attend the big cow party to be held at farm #X (1 ≤ X ≤ N). A total of M (1 ≤ M ≤ 100,000) unidirectional (one-way roads connects pairs of farms; road i requires Ti (1…
http://poj.org/problem?id=3268 题目大意:求到x距离与从x返回和的最大值 从x点到各个点最短路好求,直接用Dijkstar,但从各个点到x点却不好求,只要把路向翻转过来也变成求从x点到各个点,直接用Dijstar dist[]记录x点到各个点的最短路径距离 #include<stdio.h> #include<stdlib.h> #include<math.h> #include<string.h> #define max(a,…