Wavio Sequence Time Limit: 3000ms Memory Limit: 131072KB This problem will be judged on UVA. Original ID: 1053464-bit integer IO format: %lld      Java class name: Main   Wavio is a sequence of integers. It has some interesting properties. Wavio is o…

Wavio Sequence Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVA 10534 #include <stdio.h> #include <string.h> #include <algorithm> using namespace std; const int inf=0x3f3f3f3f; int mai…

Wavio Sequence My Tags (Edit) Source : UVA Time limit : 1 sec Memory limit : 32 M Submitted : 296, Accepted : 123 Wavio is a sequence of integers. It has some interesting properties. Wavio is of odd length i.e. L = 2 * n + 1. The first (n+1) integers…

Wavio Sequence  Wavio is a sequence of integers. It has some interesting properties. ·  Wavio is of odd length i.e. L = 2*n + 1. ·  The first (n+1) integers of Wavio sequence makes a strictly increasing sequence. ·  The last (n+1) integers of Wavio s…

题目传送门 题意:找对称的,形如:123454321 子序列的最长长度 分析:LIS的nlogn的做法,首先从前扫到尾,记录每个位置的最长上升子序列,从后扫到头同理.因为是对称的,所以取较小值*2-1再取最大值 代码: /************************************************ * Author :Running_Time * Created Time :2015-8-5 21:38:32 * File Name :UVA_10534.cpp ******…

// uva 10534 Wavio Sequence // // 能够将题目转化为经典的LIS. // 从左往右LIS记作d[i],从右往左LIS记作p[i]; // 则最后当中的min(d[i],p[i])就是这个波动序列的一半 // 在这最后的min(d[i],p[i]) * 2 + 1 的最大值就是我们所要求的答案 // // 这题開始想的最后的答案是d[i]==p[i]的时候求最大. // 可是这样是不正确的,比如n=4, // 1,3,1,0 // 最长的应该是3,可是我的答案是1,…

题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=68553#problem/B 题目要求: Wavio是一个整数序列,具有以下特性: 1.Wavio序列的长度是奇数, 即 L = 2 * n + 1; 2.Wavio序列前 n+1 个整数是递增序列 3.Wavio序列后 n+1 个整数是递减序列 如示例 1 2 3 4 5 4 3 2 1 10 最长的 Wavio序列 为 1 2 3 4 5 4 3 2 1 ,所以答案为9 题…

Brackets Sequence Time Limit: 1000ms Memory Limit: 65536KB This problem will be judged on PKU. Original ID: 114164-bit integer IO format: %lld      Java class name: Main Special Judge   Let us define a regular brackets sequence in the following way:…

题目大意 给定一个长度为n的整数序列,求个最长子序列(不一定连续),使得该序列的长度为奇数2k+1,前k+1个数严格递增,后k+1个数严格递减.注意,严格递增意味着该序列中的两个相邻数不能相同.n<=10000 题解 这个题目和POJ1836有点相似,都是从左往右搞一遍LIS,然后从右到左也搞一遍LIS,然后枚举中间点,然后选取两者的较小者*2-1就是答案了 代码: #include <iostream> #include <algorithm> #include <c…

题目大意:求一个序列中 先严格递增后严格递减的子序列的数目(要求这个子序列对称). 题目思路:正一遍DP,反一遍DP,因为n<=1e5,dp要把时间压缩到nlogn #include<stdio.h> #include<string.h> #include<iostream> #include<algorithm> #define MAXSIZE 100005 using namespace std; int dp[MAXSIZE],a[MAXSIZE…

题目链接:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=17&page=show_problem&problem=1475 Dynamic Programming. 最长增长子序列.推荐一个链接:http://www.cnblogs.com/liyukuneed/archive/2013/05/26/3090402.html.按照链接里的方法三(其他的会有TLE…

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1475 正反一次lis然后去min{左,右}*2-1即可 #include <cstdio> #include <cstring> #include <cmath> #include <string> #include <iostream&…

题意:给定一个序列,求一个最长子序列,使得序列长度为奇数,并且前一半严格递增,后一半严格递减. 析:先正向和逆向分别求一次LIS,然后再枚举中间的那个数,找得最长的那个序列. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath>…

两边算一下LIS就出来了,因为数据比较大,所以需要二分优化一下. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; + ; int n; int a[maxn], l[maxn], r[maxn]; int g[maxn]; void LIS(int d[]) { memset(g, 0x3f, sizeof(g…

题目 Volume 0. Getting Started 开始10055 - Hashmat the Brave Warrior 10071 - Back to High School Physics 10300 - Ecological Premium 458 - The Decoder 494 - Kindergarten Counting Game 414 - Machined Surfaces 490 - Rotating Sentences 445 - Marvelous Mazes…

各种杂题,水题,模拟,包括简单数论. 1001 A+B 1002 A+B+C 1009 Fat Cat 1010 The Angle 1011 Unix ls 1012 Decoding Task 1019 Grandpa's Other Estate 1034 Simple Arithmetics 1036 Complete the sequence! 1043 Maya Calendar 1054 Game Prediction 1057 Mileage Bank 1067 Rails 10…

111 - History Grading LCS 103 - Stacking Boxes 最多能叠多少个box DAG最长路 10405 - Longest Common Subsequence LCS 674 - Coin Change 全然背包求方案数 10003  - Cutting Sticks 区间DP dp[l][r]代表分割l到r的最小费用 116 - Unidirectional TSP 简单递推 输出字典序最小解 从后往前推 10131 - Is Bigger Smarte…

免费做一样新 1004 - Monkey Banana Problem 号码塔 1005 - Rooks 排列 1013 - Love Calculator LCS变形 dp[i][j][k]对于第一个字符串i 到jLCS为k的方案数 1068 - Investigation 数位dp 能被K整数且各位数字之和也能被K整除的数 dp[i][j][k] 到第i位每位数字之和的余数为j 当前数字余数为k 1079 - Just another Robbery 01背包 全部钱之和为背包体积 不被抓的…

本文出自   http://blog.csdn.net/shuangde800 刘汝佳<算法竞赛入门经典-训练指南>的动态规划部分的习题Beginner  打开 这个专题一共有25题,刷完后对dp的感觉提升了不少. 现把解题报告整理了一下,希望对大家能有帮助. 入门习题 (Exercises: Beginner) UVa11584 Partitioning by Palindromes 入门题目 LA4256 Salesman 入门题目 UVa10534 Wavio Sequence 可以转化…

1.UVa 11584 Partitioning by Palindromes(字符串区间dp) 题意:给出一个字符串,划分为若干字串,保证每个字串都是回文串,同时划分数目最小. 思路:dp[i]表示以第i位结尾时最小的划分数目(初始均为0) 状态转移方程1:(初始均为0)当[j:i]是回文串(0≤j≤i,0≤i<n):dp[i]=1(j==0);dp[i]=(dp[i]==0?dp[j-1]+1:min(dp[i],dp[j-1]+1)) 状态转移方程2:(初始:dp[i]=i+1)当[j:i…

oracle创建序列化: CREATE SEQUENCE seq_itv_collection            INCREMENT BY 1  -- 每次加几个              START WITH 1399       -- 从1开始计数              NOMAXVALUE        -- 不设置最大值              NOCYCLE               -- 一直累加,不循环              CACHE 10; oracle修改序列…

功能:备份存储过程,视图,函数触发器,Sequence序列号等准备工作:--1.创建文件夹 :'E:/OracleBackUp/ProcBack';--文本存放的路径--2.执行:create or replace directory MyProcBakPath as 'E:/OracleBackUp/ProcBack';--3.赋权限:sqlplus /nologconn user/pswd as sysdbagrant select on DBA_OBJECTS to user;--4.创建…

环境:Oracle 11.2.0.4 DG 故障现象: 客户在备库告警日志中发现GAP sequence提示信息: Mon Nov 21 09:53:29 2016 Media Recovery Waiting for thread 1 sequence 12034 Fetching gap sequence in thread 1, gap sequence 12034-12078 Mon Nov 21 09:55:20 2016 FAL[client]: Failed to request…

The set [1,2,3,-,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…

Check whether the original sequence org can be uniquely reconstructed from the sequences in seqs. The org sequence is a permutation of the integers from 1 to n, with 1 ≤ n ≤ 104. Reconstruction means building a shortest common supersequence of the se…

Given a binary tree, find the length of the longest consecutive sequence path. The path refers to any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The longest consecutive path need to be from p…

Given an array of numbers, verify whether it is the correct preorder traversal sequence of a binary search tree. You may assume each number in the sequence is unique. Follow up: Could you do it using only constant space complexity? 这道题让给了我们一个一维数组,让我们…

Given an unsorted array of integers, find the length of the longest consecutive elements sequence. For example, Given [100, 4, 200, 1, 3, 2], The longest consecutive elements sequence is [1, 2, 3, 4]. Return its length: 4. Your algorithm should run i…

The set [1,2,3,…,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…

The set [1,2,3,-,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…