Choose the best route--hdu2680】的更多相关文章

Choose the best route Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 8224    Accepted Submission(s): 2706 Problem Description One day , Kiki wants to visit one of her friends. As she is liable…
Choose the best route Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 86   Accepted Submission(s) : 35 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description One day , Kiki…
题目链接: Choose the best route Time Limit: 2000/1000 MS (Java/Others)     Memory Limit: 32768/32768 K (Java/Others) Problem Description   One day , Kiki wants to visit one of her friends. As she is liable to carsickness , she wants to arrive at her frie…
题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=2680 Choose the best route Description One day , Kiki wants to visit one of her friends. As she is liable to carsickness , she wants to arrive at her friend’s home as soon as possible . Now give you a ma…
http://acm.hdu.edu.cn/showproblem.php?pid=2680 Choose the best route Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 9602    Accepted Submission(s): 3111 Problem Description One day , Kiki wants…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2680 Choose the best route Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7201    Accepted Submission(s): 2350 Problem Description One day , Kiki…
Choose the best route Problem Description One day , Kiki wants to visit one of her friends. As she is liable to carsickness , she wants to arrive at her friend’s home as soon as possible . Now give you a map of the city’s traffic route, and the stati…
https://vjudge.net/problem/HDU-2680 题意:以起始点 终点 长度 给出一个图,已知可以从w个起点出发,求从任一起点到同一个终点s的最短路径.注意是单向边.m<1e5,w<n<1000. 题解:若每个起点都dijkstra一遍时间复杂度为O((E+VlogV)*V),会TLE,想了一下,终点当成起点,反向建边就可以了 坑点:做图论习题一度因为没看到directed,directional,wa到怀疑dijkstra错了 ac代码,用的邻接表存图及优先队列d…
题目 题意:给定一个有向图,多个起点,一个终点,求起点到终点的最短路. 这道题TLE了好多次,两侧次的对比主要在于对起点的处理上,法一:最开始是采用的hdu2066--一个人的旅行,这道题的方法做的,发现总是TLE. 法二:然后看别人的博客:再加上一个点作为起点,编号为0,这个点和题中给的那些起点之间的距离为0.这样题目就转化为了求单源最短路径问题. 当时我觉得这两种做法没有什么不同,结果我错了.法一:每个起点都要去运行一边 Dijkstra算法,而法二:只用运行一次Dijkstra算法,所以法…
此题中起点有1000个,边有20000条.用链式前向星建图,再枚举起点用SPFA的话,超时了.(按理说,两千万的复杂度应该没超吧.不过一般说计算机计算速度 1~10 千万次/秒.也许拿最烂的计算机来卡时间) 有一个技巧,加一个超级源点.也就是加一个点,使得该点连通所有的起点,并且边的权值为0.这个技巧应用蛮多的.网络流.最小树形图都有题目这样做. #include<iostream> #include<cstdio> #include<cstring> #include…