POJ 1045：Bode Plot

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Bode Plot Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 13392 Accepted: 8462 Description Consider the AC circuit below. We will assume that the circuit is in steady-state. Thus, the voltage at nodes 1 and 2 are given by v1 = VS coswt…

POJ1045 Bode Plot

题目来源:http://poj.org/problem?id=1045 题目大意: 如图所示的交流电路,假设电路处于稳定状态,Vs为电源电压,w是频率,单位为弧度每秒,t表示时间. 则:V1 = Vs * cos (wt); V2 = VR * cos(wt + q). 其中VR为电阻R两端电压下降的幅度,q是相位.写一个程序确定不同的w对于的VR值.相关的两个电学公式: 欧姆定理:V2 = i*R, i为电流大小 i = C d/dt(V1 - V2). 输入:包括一行或多行.第一行包括三个实…

九度oj 题目1045：百鸡问题

题目1045:百鸡问题时间限制:1 秒内存限制:32 兆特殊判题:否提交:10418 解决:4559 题目描述: 用小于等于n元去买100只鸡,大鸡5元/只,小鸡3元/只,还有1/3元每只的一种小鸡,分别记为x只,y只,z只.编程求解x,y,z所有可能解. 输入: 测试数据有多组,输入n. 输出: 对于每组输入,请输出x,y,z所有可行解,按照x,y,z依次增大的顺序输出. 样例输入: 40 样例输出: x=0,y=0,z=100 x=0,y=1,z=99 x=0,y=2,z=98 x=…

POJ 3321：Apple Tree + HDU 3887：Counting Offspring（DFS序+树状数组）

http://poj.org/problem?id=3321 http://acm.hdu.edu.cn/showproblem.php?pid=3887 POJ 3321: 题意:给出一棵根节点为1的边不一定的树,然后给出问题:询问区间和或者节点值更新. HDU 3887: 题意:和POJ 3321的题意差不多,只不过对每个节点询问不包含该节点的区间和思路:今天才学了下才知道有DFS序这种东西,加上树状数组处理一下区间和和节点更新. DFS序大概就是我们在DFS遍历一棵树的时候,在进…

POJ 3252：Round Numbers

POJ 3252:Round Numbers Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 10099 Accepted: 3669 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Sciss…

1045 Bode Plot

题目链接:http://poj.org/problem?id=1045 一道数学物理题, 推理公式:http://www.cnblogs.com/rainydays/archive/2013/01/08/2851741.html 代码: #include <iostream> #include <iomanip> #include <cmath> using namespace std; int main(){ double VS,R,C,w; cin>>V…

[POJ] Bode Plot

Description Consider the AC circuit below. We will assume that the circuit is in steady-state. Thus, the voltage at nodes 1 and 2 are given by v1 = VS coswt and v2 = VRcos (wt + q ) where VS is the voltage of the source, w is the frequency (in radian…