二叉查找树迭代器 · Binary Search Tree Iterator

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二叉查找树迭代器 · Binary Search Tree Iterator

［抄题］: 设计实现一个带有下列属性的二叉查找树的迭代器: 元素按照递增的顺序被访问(比如中序遍历) next()和hasNext()的询问操作要求均摊时间复杂度是O(1) 对于下列二叉查找树,使用迭代器进行中序遍历的结果为 [1, 6, 10, 11, 12] 10 / \ 1 11 \ \ 6 12 ［思维问题］: ［一句话思路］: 有next就全部进入stack并设末尾为空,同时有没有和stack的结果相反. 弹出一个点的同时,next要设置成cur.right,重新入栈.因为next需要…

[Swift]LeetCode173. 二叉搜索树迭代器 | Binary Search Tree Iterator

Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in average O(1) time and uses…

leetcode-173：Binary Search Tree Iterator（Java）

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Binary Search Tree Iterator Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in…

二叉树前序、中序、后序非递归遍历 144. Binary Tree Preorder Traversal 、 94. Binary Tree Inorder Traversal 、145. Binary Tree Postorder Traversal 、173. Binary Search Tree Iterator

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✡ leetcode 173. Binary Search Tree Iterator 设计迭代器（搜索树）--------- java

Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in average O(1) time and uses…

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Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in average O(1) time and uses…

[leetcode]173. Binary Search Tree Iterator 二叉搜索树迭代器

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leetcode 173. Binary Search Tree Iterator

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LeetCode——Binary Search Tree Iterator

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LeetCode（173） Binary Search Tree Iterator

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【leetcode】Binary Search Tree Iterator（middle）

Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in average O(1) time and uses…

Binary Search Tree Iterator

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LeetCode Binary Search Tree Iterator

原题链接在这里:https://leetcode.com/problems/binary-search-tree-iterator/ Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. N…

【LeetCode 173】Binary Search Tree Iterator

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173. Binary Search Tree Iterator

题目: Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in average O(1) time and u…

leetcode@ [173] Binary Search Tree Iterator (InOrder traversal)

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Binary Search Tree Iterator 解答

Question Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in average O(1) time…

【原创】leetCodeOj --- Binary Search Tree Iterator 解题报告

时间挤挤总是有的太久不做题,脑子都生锈了.来道水题练练手题目地址: https://leetcode.com/problems/binary-search-tree-iterator/ 题目内容: Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the…

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Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in average O(1) time and uses…

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Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in average O(1) time and uses…

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LC 173. Binary Search Tree Iterator

题目描述 Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Example: BSTIterator iterator = new BSTIterator(root); iterator…