PKU OJ 1002 487-3279 487-3279 Description Businesses like to have memorable telephone numbers. One way to make a telephone number memorable is to have it spell a memorable word or phrase. For example, you can call the University of Waterloo by dialin…
时间限制:1 秒 内存限制:32 兆 特殊判题:否 提交:18410 解决:4753 题目描述: Grading hundreds of thousands of Graduate Entrance Exams is a hard work. It is even harder to design a process to make the results as fair as possible. One way is to assign each exam problem to 3 indep…
#include <stdio.h> #include <string.h> int main(void) { int q,j,h,k,l; int d; ],s2[];//题目要求位数不大于1000 scanf("%d",&h); ;l<=h;l++){ ]={}, a[]={},b[]={};//这样可以令数组内全部元素为0 scanf("%s %s",&s1,&s2); int cd1,cd2,cd3,cd…
#include<iostream> #include<queue> #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> using namespace std; ][]; int main(){ int P,T,G1,G2,G3,GJ; while(cin>>P>>T>>G1>>G2>>…
[z]http://jingyan.baidu.com/article/5d368d1e182bb93f60c05784.html START WITH CONNECT BY PRIOR这个语法主要用于查询数据包中的树型结构关系.先看下原始数据时怎么样的吧! 表中第一行1001是1002的父节点,而第二行1002又是1003的父节点,如此循环.如题:要求给出其中一个数字能找出其最终的根节点!应该要怎么样实现呢?请看如下sql语句,这里我就拿1008为例.图中第一行第一个num1就是根节点了.再来…