Let's say we have two strings: str1 = 'ACDEB' str2 = 'AEBC' We need to find the longest common subsequence, which in this case should be 'AEB'. Using dynamic programming, we want to compare by char not by whole words. we need memo to keep tracking th…

首先来看什么是最长公共子序列:给定两个序列,找到两个序列中均存在的最长公共子序列的长度.子序列需要以相关的顺序呈现,但不必连续.例如,"abc", "abg", "bdf", "aeg", '"acefg"等都是"abcdefg"的子序列.因此,一个长度为n的序列拥有2^n中可能的子序列(序列中的每一个元素只有选或者不选两种可能,因此是2^n). Example: LCS for inp…

在 Dynamic Programming | Set 1 (Overlapping Subproblems Property) 和 Dynamic Programming | Set 2 (Optimal Substructure Property) 中我们已经讨论了重叠子问题和最优子结构性质,现在我们来看一个可以使用动态规划来解决的问题:最长上升子序列(Longest Increasing Subsequence(LIS)). 最长上升子序列问题,致力于在一个给定的序列中找到一个最长的子序列…

1. 问题描述 子串应该比较好理解,至于什么是子序列,这里给出一个例子:有两个母串 cnblogs belong 比如序列bo, bg, lg在母串cnblogs与belong中都出现过并且出现顺序与母串保持一致,我们将其称为公共子序列.最长公共子序列(Longest Common Subsequence, LCS),顾名思义,是指在所有的子序列中最长的那一个.子串是要求更严格的一种子序列,要求在母串中连续地出现.在上述例子的中,最长公共子序列为blog(cnblogs, belong),最长公…

The Longest Common Subsequence (LCS) problem is as follows: Given two sequences s and t, find the length of the longest sequence r, which is a subsequence of both s and t. Do you know the difference between substring and subequence? Well, substring i…

link to problem Description: Given two strings text1 and text2, return the length of their longest common subsequence. A subsequence of a string is a new string generated from the original string with some characters(can be none) deleted without chan…

Longest Common Subsequence Accepted : Submit : Time Limit : MS Memory Limit : KB Longest Common Subsequence Bobo has a sequence A=(a1,a2,…,an) of length n. He would like to know f(),f(),f() and f() where f(k) denotes the number of integer sequences X…

''' merge two configure files, basic file is aFile insert the added content of bFile compare to aFile for example, 'bbb' is added content ----------------------------------------------------------- a file content | b file content | c merged file cont…

[牛客网]Longest Common Subsequence 发现只有d数组最格路 于是我们把前三个数组中相同的数记成一个三维坐标,同一个数坐标不会超过8个 从前往后枚举d,每次最多只会更新不超过8个点 而每个点更新就是找这个点三维偏序都小于它的最大的一个值+1来更新它 用KD树来维护,这个点与树中节点三维的某一维不相交就退出 可以加的剪枝是如果树中最大值+1小于当前搜到的答案就退出 然后把新的值在树中进行更新 跑的还是挺快的,0.5s不到 #include <bits/stdc++.h>…

原题链接在这里:http://www.lintcode.com/en/problem/longest-common-subsequence/ 题目: Given two strings, find the longest common subsequence (LCS). Your code should return the length of LCS. Clarification What's the definition of Longest Common Subsequence? htt…