Connect the Cities Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 13722    Accepted Submission(s): 3711 Problem Description In 2100, since the sea level rise, most of the cities disappear. Tho…

题目描述: 有n个小岛,其中有的小岛之间没有通路,要修这样一条通路需要花费一定的钱,还有一些小岛之间是有通路的.现在想把所有的岛都连通起来,求最少的花费是多少. 输入: 第一行输入T,代表多少组数据. 第二行输入三个整数n , m , k,分别代表一共有n个小岛,m条路径可供选择,k表示有连通岛的个数. 接下来的m行,每行三个整数p , q , c ,代表建设p到q的通路需要花费的钱为c. 接下的k行,每一行的数据输入如下:先输入Q,代表这个连通分量里面有Q个小岛,然后输入Q个小岛,代表这Q个小…

Connect the Cities Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 18322 Accepted Submission(s): 4482 Problem DescriptionIn 2100, since the sea level rise, most of the cities disappear. Though some…

Connect the Cities Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7338    Accepted Submission(s): 2093 Problem Description In 2100, since the sea level rise, most of the cities disappear. Thou…

Connect the Cities Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 3371 Description In 2100, since the sea level rise, most of the cities disappear. Though some survived cities are still connect…

这个时间短 700多s #include<stdio.h> #include<string.h> #include<iostream> #include<algorithm> using namespace std; struct node{ int u; int v; int w; }que[100000]; int father[505]; bool cmp(struct node a,struct node b){ return a.w<b.w;…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=3371 Connect the Cities Description In 2100, since the sea level rise, most of the cities disappear. Though some survived cities are still connected with others, but most of them become disconnected. The…

Connect the Cities Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 12903    Accepted Submission(s): 3549 Problem Description In 2100, since the sea level rise, most of the cities disappear. Thou…

Connect the Cities Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 4   Accepted Submission(s) : 3 Problem Description In 2100, since the sea level rise, most of the cities disappear. Though some…

Connect the Cities Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 701 Accepted Submission(s): 212   Problem Description In 2100, since the sea level rise, most of the cities disappear. Though som…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=3371 Problem Description In 2100, since the sea level rise, most of the cities disappear. Though some survived cities are still connected with others, but most of them become disconnected. The governmen…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=3371 984ms风险飘过~~~ /************************************************************************/ /* hdu Connect the Cities 最小生成树 题目大意:最小生成树,题目很长,题意很简单就是最小生成树.关键是构建图 */ /****************************************…

Connect the Cities Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 9985    Accepted Submission(s): 2843 Problem Description In 2100, since the sea level rise, most of the cities disappear. Thou…

注意输入的数据分别是做什么的就好.还有,以下代码用C++交可以过,而且是500+ms,但是用g++就会TLE,很奇怪. #include <iostream> #include <cstring> #include <cstdio> #include <cstdlib> #include <cmath> #include <cctype> #include <algorithm> #include <numeric&…

题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=3371 题目不难 稍微注意一下 要把已经建好的城市之间的花费定义为0,在用普通Prim算法就可以了:我没有用克鲁斯卡尔算法(Kruskal's algorithm),因为这题数据比较大,而且要处理大量的数据使它为0,怕超时T^T..... #include<iostream> #include<cstdio> #include<algorithm> using namespa…

地址:http://acm.hdu.edu.cn/showproblem.php?pid=3371 其实就是最小生成树,但是这其中有值得注意的地方:就是重边.题目没有告诉你两个城市之间只有一条路可走,所以两个城市之间可能有多条路可以走. 举例: 输入可以包含 1 2 3  // 1到2的成本为3   1 2 5  //1到2的成本为5      因此此时应选成本较低的路. 然后,已经连通的城市之间的连通成本为0. 这题用G++提交得到984ms的反馈,用C++提交则得到484ms的反馈. 很想知…

解题报告:有n个点,然后有m条可以添加的边,然后有一个k输入,表示一开始已经有k个集合的点,每个集合的点表示现在已经是连通的了. 还是用并查集加克鲁斯卡尔.只是在输入已经连通的集合的时候,通过并查集将该集合的点标记到一起,然后剩下的就可以当成是普通的最小生成树来做了题目代码如下: #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #include<cstd…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=3371 题目大意: 给n个城市,m条路,k组已知路,求最小费用联通所有城市: 解题思路: kruskal求MST,这道题目有毒,很容易超时,改了一下并查集才过,而且同一个代码有时过又是超时 #include<bits/stdc++.h> using namespace std; typedef long long ll; + ; const int INF = 0x3f3f3f3f; int p[…

//我看过Discuss说不能用克鲁斯卡尔因为有很多边 //但是只能用G++过,C++的确超时 #include <stdio.h> #include <string.h> #include <algorithm> using namespace std; struct node { int a, b, cost; }c[]; ]; void init(int n) { ; i <= n; i++) fa[i] = i; } bool cmp(node x, no…

题目网址:http://acm.hdu.edu.cn/showproblem.php?pid=3371 思路: 这道题很明显是一道最小生成树的题目,有点意思的是,它事先已经让几个点联通了.正是因为它先联通了几个点,所以为了判断连通性 很容易想到用并查集+kruskal. 不过要注意 这题有一个坑点,就是边数很多 上限是25000,排序的话可能就超时了.而点数则比较少 上限是500,所以很多人选择用Prim做.但我个人觉得这样连通性不好判断.其实边数多没关系,我们只要去重就好啦,用邻接矩阵存下两点…

http://acm.hdu.edu.cn/showproblem.php?pid=3371 AC代码: /** /*@author Victor /* C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string…

Connect the Cities Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 18067    Accepted Submission(s): 4460 Problem Description In 2100, since the sea level rise, most of the cities disappear. Thou…

Problem Description In 2100, since the sea level rise, most of the cities disappear. Though some survived cities are still connected with others, but most of them become disconnected. The government wants to build some roads to connect all of these c…

http://codeforces.com/contest/962/problem/E E. Byteland, Berland and Disputed Cities time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The cities of Byteland and Berland are located on the a…

Connect the Cities Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7997    Accepted Submission(s): 2267 Problem Description In 2100, since the sea level rise, most of the cities disappear. Thoug…

Connect the Cities Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 13299 Accepted Submission(s): 3618 Problem Description In 2100, since the sea level rise, most of the cities disappear. Though so…

Connect the Cities Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 7   Accepted Submission(s) : 5 Problem Description In 2100, since the sea level rise, most of the cities disappear. Though some…

Battle over Cities Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 467    Accepted Submission(s): 125 Problem Description It is vitally important to have all the cities connected by highways in…

原题链接在这里:https://leetcode.com/problems/connecting-cities-with-minimum-cost/ 题目: There are N cities numbered from 1 to N. You are given connections, where each connections[i] = [city1, city2, cost] represents the cost to connect city1 and city2together…

E. Byteland, Berland and Disputed Cities time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output The cities of Byteland and Berland are located on the axis Ox. In addition, on this axis there are also…