题目:找出能被两个给定参数和它们之间的连续数字整除的最小公倍数.  范围是两个数字构成的数组,两个数字不一定按数字顺序排序. 分析:首先题目的意思求一个连续数列的所有数字的最小公倍数,这连续的数字序列可能递增,也可能递减,有两种情况,为了使代码简洁, 我们将其变为一种情况,也就是递增数列,这样避免重复写递减数列的情况.再一看,这里说了参数是数组,那么可以使用sort()方法排序.    这道题其实只要懂得怎么求两个数之间的最小公倍数,就可以求这个序列的最小公倍数了.因为,最小公倍数也是一个数字,…

题目 找出能被两个给定参数和它们之间的连续数字整除的最小公倍数. 范围是两个数字构成的数组,两个数字不一定按数字顺序排序. 例如对 1 和 3 —— 找出能被 1 和 3 和它们之间所有数字整除的最小公倍数. 提示 Smallest Common Multiple 测试用例 smallestCommons([1, 5]) 应该返回一个数字. smallestCommons([1, 5]) 应该返回 60. smallestCommons([5, 1]) 应该返回 60. smallestComm…

Map the Debris 1.要求 返回一个数组,其内容是把原数组中对应元素的平均海拔转换成其对应的轨道周期. 原数组中会包含格式化的对象内容,像这样 {name: 'name', avgAlt: avgAlt}. 求得的值应该是一个与其最接近的整数,轨道是以地球为基准的. 地球半径是 6367.4447 kilometers, 地球的GM值是 398600.4418, 圆周率为Math.PI 至于轨道周期怎么求,下面相关链接第一个 2.思路 查找资料得到计算轨道周期相关公式: GMm/R^…

存档. 找出能被两个给定参数和它们之间的连续数字整除的最小公倍数. function smallestCommons(arr) { //分解质因数法,分解为若干个质数相乘 var arrratio=[]; var min=Math.min(arr[0],arr[1]); var max=Math.max(arr[0],arr[1]); for(var i=min+1;i<max;i++){ arr.push(i); } //找出小于max的所有质数 var arrtemp=[]; for(var…

FCC题目:找出能被两个给定参数和它们之间的连续数字整除的最小公倍数. 范围是两个数字构成的数组,两个数字不一定按数字顺序排序. 例如对 1 和 3 -- 找出能被 1 和 3 和它们之间所有数字整除的最小公倍数. 示例: smallestCommons([1, 5])应该返回一个数字. smallestCommons([1, 5])应该返回 60. smallestCommons([5, 1])应该返回 60. smallestCommons([1, 13]) 应该返回 360360. 步骤:…

Spinal Tap Case 1.要求 将字符串转换为 spinal case. Spinal case 是 all-lowercase-words-joined-by-dashes 这种形式的,也就是以连字符连接所有小写单词. 2.思路 用.replace()和正则表达式把小写字母和大写字母之间用空格隔开 再 3.再用.replace()把空格替换成'-',最后小写化即可 function spinalCase(str) { var regex = /\s+|_+/g; str = str.…

Search and Replace 1.要求 使用给定的参数对句子执行一次查找和替换,然后返回新句子. 第一个参数是将要对其执行查找和替换的句子. 第二个参数是将被替换掉的单词(替换前的单词). 第三个参数用于替换第二个参数(替换后的单词). 替换时保持原单词的大小写.例如,如果你想用单词 "dog" 替换单词 "Book" ,你应该替换成 "Dog". 2.思路 将句子用.split(' ')分割成各个单词组成的数组 判断要被替换的的单词是否…

Smallest Common Multiple 1.要求 找出能被两个给定参数和它们之间的连续数字整除的最小公倍数. 2.思路 设定一个twoMultiple(a,b)函数,求出输入两个参数的最小公倍数 设定结果变量res,初始为给定两个参数的最小值 在主函数中设定从给定两个参数最小值到最大值的循环 在主函数循环中运行twoMultiple(res,i+1),得出两个给定参数和它们之间的连续数字整除的最小公倍数 3.代码 function twoMultiple(a,b){//计算两个数最小公…

[九度OJ]题目1439:Least Common Multiple 解题报告 标签(空格分隔): 九度OJ 原题地址:http://ac.jobdu.com/problem.php?pid=1439 题目描述: The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set…

题目链接:http://ac.jobdu.com/problem.php?pid=1439 详解链接:https://github.com/zpfbuaa/JobduInCPlusPlus 参考代码: // // 1439 Least Common Multiple.cpp // Jobdu // // Created by PengFei_Zheng on 10/04/2017. // Copyright © 2017 PengFei_Zheng. All rights reserved. /…

LeetCode算法题目解答汇总 本文转自<四火的唠叨> 只要不是特别忙或者特别不方便,最近一直保持着每天做几道算法题的规律,到后来随着难度的增加,每天做的题目越来越少.我的初衷就是练习,因为一方面我本身算法基础并不好,再一方面是因为工作以后传统意义上所谓算法的东西接触还是太少.为了题目查找方便起见,我把之前几篇陆陆续续贴出来的我对LeetCode上面算法题的解答汇总在下面,CTRL+F就可以比较方便地找到.由于LeetCode上的题在不断更新,因此我也会不定期地更新.下面表格里面的Accep…

Least Common Multiple (HDU - 1019) [简单数论][LCM][欧几里得辗转相除法] 标签: 入门讲座题解 数论 题目描述 The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7…

题目地址:http://ac.jobdu.com/problem.php?pid=1056 题目描述: 输入两个正整数,求其最大公约数. 输入: 测试数据有多组,每组输入两个正整数. 输出: 对于每组输入,请输出其最大公约数. 样例输入: 49 14 样例输出: 7 来源: 2011年哈尔滨工业大学计算机研究生机试真题 #include <stdio.h> int gcd1 (int a, int b){ if (b == 0) return a; else return gcd1 (b, a…

***************************************转载请注明出处:http://blog.csdn.net/lttree*************************************** Least Common Multiple Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 28975    …

Least Common Multiple Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 53016    Accepted Submission(s): 20171 Problem Description The least common multiple (LCM) of a set of positive integers is…

太简单了...题目都不想贴了 //算n个数的最小公倍数 #include<cstdio> #include<cstring> #include<algorithm> using namespace std; int gcd(int a, int b) { ?a:gcd(b,a%b); } int lcm(int a, int b) { return a/gcd(a,b)*b; } int main() { int T; scanf("%d",&…

题目:Least common multiple 链接:http://acm.hdu.edu.cn/showproblem.php?pid=4913 题意:有一个集合s,包含x1,x2,...,xn,有xi=2^ai * 3^bi,然后给你a数组和b数组,求s所有子集合的最小公倍数之和.比如S={18,12,18},那么有{18},{12},{18},{18,12},{18,18},{12,18},{18,12,18},所以答案是174. 思路: 1. 最小公倍数,因为xi只包含两个质因子2.3…

地址:http://acm.hdu.edu.cn/showproblem.php?pid=1019 题目: Problem Description The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 an…

题目描述 The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105. 输入 Input will consist of multiple problem instances. The…

Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Description The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. Fo…

Problem Description The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.   Input Input will consist of multiple pr…

http://acm.hdu.edu.cn/showproblem.php?pid=1019 Least Common Multiple Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 25035    Accepted Submission(s): 9429 Problem Description The least common m…

地址:http://www.codewars.com/kata/5259acb16021e9d8a60010af/train/python 题目: Write a function that calculates the least common multiple of its arguments; each argument is assumed to be a non-negative integer. 代码: def lcm2(a,b): m = max(a,b) n = min(a,b)…

Problem Description The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.   Input Input will consist of multiple pr…

Problem Description The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105. Input Input will consist of multiple prob…

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 51959    Accepted Submission(s): 19706   Problem Description The least common multiple (LCM) of a set of positive integers is the smallest positiv…

Least Common Multiple Time Limit: 2 Seconds      Memory Limit: 65536 KB The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and…

The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105. InputInput will consist of multiple problem instances. The fi…

The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.   InputInput will consist of multiple problem instances. The…

[ZOJ2069]Greatest Least Common Multiple 题目大意: 给定一个正整数\(n\),将其分成若干个正整数之和,最大化这些数的LCM.保证答案小于\(10^{25}\). 思路: 由于答案\(\le10^{25}\),则\(n\le540\). 可以证明一定存在一种方案使得拆分后各数互质且答案最大. \(f[i][j]\)表示考虑前\(i\)种质数,组成的和为\(j\)的答案.转移时枚举从\(n\)中拆出这个质数的多少次方. 由于OJ上不支持__int128,所以…