Matrix Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 25004   Accepted: 9261 Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (1…

Matrix Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 16950   Accepted: 6369 Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (1…

Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (1 <= i, j <= N).  We can change the matrix in the following way. Given a rectangle whose up…

[pixiv] https://www.pixiv.net/member_illust.php?mode=medium&illust_id=34310873 Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (1 <= i, j &…

Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (1 <= i, j <= N). We can change the matrix in the following way. Given a rectangle whose upp…

                                                                                                               Matrix Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 15125   Accepted: 5683 Description Given an N*N matrix A, whose element…

Matrix Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 20599   Accepted: 7673 Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (1…

Matrix Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 21757   Accepted: 8141 Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (1…

转自:http://blog.csdn.net/sdj222555/article/details/10828607 大意就是给出一个矩阵 初始每个位置上的值都为0 然后有两种操作 一种是更改某个位置上的值 另一个是求某个位置附近曼哈顿距离不大于K的所有位置的值的总和 然后这里用了一个非常牛叉的技巧 将所有点绕原点左旋45° 然后新的坐标也很好计算 x' = (x - y) * sqrt(2) / 2 y' = (x + y) * sqrt(2) / 2 由于都是小数 所以乘个sqrt(2) 就…

题意:给你一个矩阵开始全是0,然后给你两种指令,第一种:C x1,y1,x2,y2 就是将左上角为x1,y1,右下角为x2,y2,的这个矩阵内的数字全部翻转,0变1,1变0 第二种:Q x1 y1,输出举证x1,y1,位置的数值 思路:该题的巧妙之处是反转的重叠抵消,记住要向上统计,向下修改:二维情况,最主要的是理解那个数组中的每个点保存的值的意义(一个矩形区域的总和):最后记住取余: 此题参考博客 http://blog.csdn.net/xymscau/article/details/660…