Gold Balanced Lineup POJ - 3274】的更多相关文章

Description Farmer John's N cows (1 ≤ N ≤ 100,000) share many similarities. In fact, FJ has been able to narrow down the list of features shared by his cows to a list of only K different features (1 ≤ K ≤ 30). For example, cows exhibiting feature #1…
这题,看到别人的解题报告做出来的,分析: 大概意思就是: 数组sum[i][j]表示从第1到第i头cow属性j的出现次数. 所以题目要求等价为: 求满足 sum[i][0]-sum[j][0]=sum[i][1]-sum[j][1]=.....=sum[i][k-1]-sum[j][k-1] (j<i) 中最大的i-j 将上式变换可得到 sum[i][1]-sum[i][0] = sum[j][1]-sum[j][0] sum[i][2]-sum[i][0] = sum[j][2]-sum[j]…
Gold Balanced Lineup Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 10924 Accepted: 3244 Description Farmer John's N cows (1 ≤ N ≤ 100,000) share many similarities. In fact, FJ has been able to narrow down the list of features shared by h…
Gold Balanced Lineup Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 13540   Accepted: 3941 Description Farmer John's N cows (1 ≤ N ≤ 100,000) share many similarities. In fact, FJ has been able to narrow down the list of features shared…
Gold Balanced Lineup Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 13215 Accepted: 3873 Description Farmer John's N cows (1 ≤ N ≤ 100,000) share many similarities. In fact, FJ has been able to narrow down the list of features shared by h…
1702: [Usaco2007 Mar]Gold Balanced Lineup 平衡的队列 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 510  Solved: 196[Submit][Status][Discuss] Description Farmer John's N cows (1 <= N <= 100,000) share many similarities. In fact, FJ has been able to narrow…
P1360 [USACO07MAR]Gold Balanced Lineup G (前缀和+思维) 前言 题目链接 本题作为一道Stl练习题来说,还是非常不错的,解决的思维比较巧妙 算是一道不错的题 思路分析 第一眼看到这题,我还以为是数据结构题,看来半天没看出来数据结构咋做(我还是太菜了) 我们对\(m\)种能力有\(n\)次操作,需要找到对每种能力提升相同的最大操作区间的长度,求最大 区间,我们考虑维护这\(m\)种技能提升值的前缀和,假设第\(l+1\)次操作到第\(r\)次操作对\(m\…
题目:http://poj.org/problem?id=3274 #include <iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<stack> #include<queue> #include<iomanip> #include<cmath> #include<map> #include<ve…
http://poj.org/problem?id=3274 题意 :农夫约翰的n(1 <= N <= 100000)头奶牛,有很多相同之处,约翰已经将每一头奶牛的不同之处,归纳成了K种特性,比如1号特性代表它身上有斑点,2号特性代表它比较喜欢用passcal 写程序而不是C .约翰使用“特性标识符”来描述奶牛的各种特性,例如:一头奶牛的特性标识符是13,将13写成二进制1101,从右向左看,就表示这头奶牛具有1,3,4这三个特性,但没有2号特性,约翰把n头奶牛排成一排,发现在有些连续区间里的…
Farmer John's N cows (1 ≤ N ≤ 100,000) share many similarities. In fact, FJ has been able to narrow down the list of features shared by his cows to a list of only K different features (1 ≤ K ≤ 30). For example, cows exhibiting feature #1 might have s…