In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the recurrence relation F1 = 1; F2 = 1; Fn = Fn - 1 + Fn - 2 (n > 2). DZY loves Fibonacci numbers very much. Today DZY gives you an array consisting of n integers: a1, a2, ...,…

C. DZY Loves Fibonacci Numbers time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the recurrence relation F1 = 1; F2 …

C. DZY Loves Fibonacci Numbers time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the recurrence relation F1 = 1; F2 …

參考:http://www.cnblogs.com/chanme/p/3843859.html 然后我看到在别人的AC的方法里还有这么一种神方法,他预先设定了一个阈值K,当当前的更新操作数j<K的时候,它就用一个类似于树状数组段更的方法,用一个 d数组去存内容,譬如它要在区间 [3,6]上加一段fibonacci 原来: id 0 1 2 3 4 5 6 7 8 9 10 d  0 0 0 0 0 0 0 0 0 0 0 更新: id 0 1 2 3 4 5 6  7  8  9 10 d  0…

HDU 3117 Fibonacci Numbers(斐波那契前后四位,打表+取对+矩阵高速幂) ACM 题目地址:HDU 3117 Fibonacci Numbers 题意:  求第n个斐波那契数的前四位和后四位.  不足8位直接输出. 分析:  前四位有另外一题HDU 1568,用取对的方法来做的.  后四位能够用矩阵高速幂,MOD设成10000即可了. 代码: /* * Author: illuz <iilluzen[at]gmail.com> * Blog: http://blog.c…

Fibonacci Numbers Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 81 Accepted Submission(s): 46   Problem Description The Fibonacci sequence is the sequence of numbers such that every element is e…

Portal Description 给出一个\(n(n\leq3\times10^5)\)个数的序列,进行\(m(m\leq3\times10^5)\)次操作,操作有两种: 给区间\([L,R]\)加上一个斐波那契数列,即\(\{a_L,a_{L+1},...,a_R\} \rightarrow \{a_L+F_1,a_{L+1}+F_2,...,a_R+F_{R-L+1}\}\) 询问区间\([L,R]\)的和,对\(10^9+9\)取模. 斐波那契数列:\(F_1=1,F_2=2\)且满足…

Colossal Fibonacci Numbers 想先说下最近的状态吧,已经考完试了,这个暑假也应该是最后刷题的暑假了,打完今年acm就应该会退了,但是还什么都不会呢? +_+ 所以这个暑假,一定要竭尽全力地去刷题,当然,也是能好好刷题的最后时间了. [题目链接]Colossal Fibonacci Numbers [题目类型]数学 &题意: 求Fi(f(a^b)%n) Fi()是斐波那契 &题解: 注意:unsigned时 要把%d全换成%u 数学大法好. 首先你要能看出来这是有循环…

Fibonacci Numbers [题目链接]Fibonacci Numbers [题目类型]矩阵 &题解: 后4位是矩阵快速幂求,前4位是用log加Fibonacci通项公式求,详见上一篇博客 &代码: #include <cstdio> #include <bitset> #include <iostream> #include <set> #include <cmath> #include <cstring>…

E  DZY Loves Fibonacci Numbers In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the recurrence relation F1 = 1; F2 = 1; Fn = Fn - 1 + Fn - 2 (n > 2). DZY loves Fibonacci numbers very much. Today DZY gives you an array consist…