题目: Benny has a spacious farm land to irrigate. The farm land is a rectangle, and is divided into a lot of samll squares. Water pipes are placed in these squares. Different square has a different type of pipe. There are 11 types of pipes, which is ma…

题目网址:http://acm.hdu.edu.cn/showproblem.php?pid=1198 题目: Farm Irrigation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10132    Accepted Submission(s): 4464 Problem Description Benny has a spac…

Farm Irrigation Time Limit: 2 Seconds      Memory Limit: 65536 KB Benny has a spacious farm land to irrigate. The farm land is a rectangle, and is divided into a lot of samll squares. Water pipes are placed in these squares. Different square has a di…

Farm Irrigation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6590    Accepted Submission(s): 2838 Problem Description Benny has a spacious farm land to irrigate. The farm land is a rectangle…

意甲冠军  两个农田管内可直接连接到壳体  他们将能够共享一个水源   有11种农田  管道的位置高于一定  一个农田矩阵  问至少须要多少水源 DFS的连通块问题  两个相邻农田的管道能够直接连接的话他们就属于一个连通块  题目就是求连通块个数 #include<cstdio> #include<cstring> using namespace std; const int N = 55; char mat[N][N]; int type[11][4] = { //相应11种水管…

Farm Irrigation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4977    Accepted Submission(s): 2137 Problem Description Benny has a spacious farm land to irrigate. The farm land is a rectangle…

Farm Irrigation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11188    Accepted Submission(s): 4876 Problem Description Benny has a spacious farm land to irrigate. The farm land is a rectangle…

Farm Irrigation Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 38   Accepted Submission(s) : 24 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Benny has a spacious…

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本题和HDU畅通project类似.仅仅只是畅通project给出了数的连通关系, 而此题须要自己推断连通关系,即两个水管能否够连接到一起,也是本题的难点所在. 记录状态.不断combine(),注意仅仅须要推断左方和上方即可,这样不会反复推断,并且肯定都能够遍历到全部的状态. #include<stdio.h> #include<iostream> #include<string> //记录水管的形状,每种水管用一个由'0'和'1'组成的长度为4的字符串代表, //分…