二叉查找树简介 二叉查找树(Binary Search Tree), 也成二叉搜索树.有序二叉树(ordered binary tree).排序二叉树(sorted binary tree), 是指一棵空树或者具有下列性质的的二叉树: 1. 若任意节点的左子树不空,在左子树上所有结点的值均小于或等于它的根结点的值: 2. 任意节点的右子树不空,则右子树上所有结点的值均大于它的根结点的值: 3. 任意节点的左子树.右子树也分别为二叉查找树. 4. 没有键值相等的结点(no duplicate no…

Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note:A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? 给定一个排序二叉树,然后任意交换了其中两个节点,要求在使用…

Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys…

/// Binary Search Tree - Implemenation in C++ /// Simple program to create a BST of integers and search an element in it #include<iostream> #include "cstdio" #include "queue" using namespace std; ///Definition of Node for Binary…

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.   和上一题类似,把数组换成链表,所以可以两种做法: 1.把链表换成数组,然后用上一题的方法,这样会比较慢. 2.每次找到中间的点,作为节点,然后递归,其实原理还是二分查找.   /** * Definition for singly-linked list. * public…

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 给一个排好序的数组,然后求搜索二叉树 其实就是二分法,不难. /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNo…

public TreeNode sortedListToBST(ListNode head) { if(head==null) return new TreeNode(0); ArrayList<TreeNode> arr=new ArrayList<TreeNode>(); while(head!=null) { arr.add(new TreeNode(head.val)); head=head.next; } return BST(arr,0,arr.size()-1); }…

二叉树(Binary Tree)是最简单的树形数据结构,然而却十分精妙.其衍生出各种算法,以致于占据了数据结构的半壁江山.STL中大名顶顶的关联容器--集合(set).映射(map)便是使用二叉树实现.由于篇幅有限,此处仅作一般介绍(如果想要完全了解二叉树以及其衍生出的各种算法,恐怕要写8~10篇). 1)二叉树(Binary Tree) 顾名思义,就是一个节点分出两个节点,称其为左右子节点:每个子节点又可以分出两个子节点,这样递归分叉,其形状很像一颗倒着的树.二叉树限制了每个节点最多有两个子节…

Binary Search Tree Iterator Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in…

[109-Convert Sorted List to Binary Search Tree(排序链表转换成二叉排序树)] [LeetCode-面试算法经典-Java实现][全部题目文件夹索引] 原题 Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 题目大意 给定一个升序的单链表.将它转换成一颗高度平衡的二叉树 解题思路 解法…