hdu 5692(dfs+线段树) Snacks

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hdu 5692(dfs+线段树) Snacks

题目http://acm.hdu.edu.cn/showproblem.php?pid=5692 题目说每个点至多经过一次,那么就是只能一条路线走到底的意思,看到这题的格式, 多个询问多个更新, 自然而然的就会想到线段树或者树状数组,在建树前先做处理, 用DFS将从起点0出发到任一点的距离求出, 然后将这些节点按照一条一条完整的路线的顺序建到树中, 比如样例是1---2---3 | 6 ---4----5 所以建树的其中一种顺序是1 4 5 6 2 3 .当查询的时候的区间应该是从现在这个点开始…

HDU 5877 dfs+ 线段树（或+树状树组）

1.HDU 5877 Weak Pair 2.总结:有多种做法,这里写了dfs+线段树(或+树状树组),还可用主席树或平衡树,但还不会这两个 3.思路:利用dfs遍历子节点,同时对于每个子节点au,查询它有多少个祖先av满足av<=k/au. (1)dfs+线段树 #include<iostream> #include<cstring> #include<cmath> #include<queue> #include<algorithm>…

Snacks HDU 5692 dfs序列+线段树

Snacks HDU 5692 dfs序列+线段树题意百度科技园内有n个零食机,零食机之间通过n−1条路相互连通.每个零食机都有一个值v,表示为小度熊提供零食的价值. 由于零食被频繁的消耗和补充,零食机的价值v会时常发生变化.小度熊只能从编号为0的零食机出发,并且每个零食机至多经过一次.另外,小度熊会对某个零食机的零食有所偏爱,要求路线上必须有那个零食机. 为小度熊规划一个路线,使得路线上的价值总和最大输入输出: 输入数据第一行是一个整数T(T≤10),表示有T组测试数据. 对于每组数据,…

hdu 4031 attack 线段树区间更新

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hdu 4288 离线线段树+间隔求和

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hdu 3016 dp+线段树

Man Down Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2030 Accepted Submission(s): 743 Problem Description The Game “Man Down 100 floors” is an famous and interesting game.You can enjoy t…

Codeforces1110F Nearest Leaf dfs + 线段树 + 询问离线

Codeforces1110F dfs + 线段树 + 询问离线 F. Nearest Leaf Description: Let's define the Eulerian traversal of a tree (a connected undirected graph without cycles) as follows: consider a depth-first search algorithm which traverses vertices of the tree and enu…