hihocoder 1135 : Magic Box

【hihocoder 1135 : Magic Box】的更多相关文章

hihocoder 1135 : Magic Box

#1135 : Magic Box 时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 The circus clown Sunny has a magic box. When the circus is performing, Sunny puts some balls into the box one by one. The balls are in three colors: red(R), yellow(Y) and blue(B). Let Cr, Cy, C…

【hihocoder】 Magic Box

题目1 : Magic Box 时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 The circus clown Sunny has a magic box. When the circus is performing, Sunny puts some balls into the box one by one. The balls are in three colors: red(R), yellow(Y) and blue(B). Let Cr, Cy, Cb…

微软2016校园招聘在线笔试之Magic Box

题目1 : Magic Box 时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 The circus clown Sunny has a magic box. When the circus is performing, Sunny puts some balls into the box one by one. The balls are in three colors: red(R), yellow(Y) and blue(B). Let Cr, Cy, Cb…

hihoCoder#1135

刚开始学习C语言,准备在做hiho的题目的过程中来学习,在此进行记录,如果代码中有错误或者不当的地方还请指正. 时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 The circus clown Sunny has a magic box. When the circus is performing, Sunny puts some balls into the box one by one. The balls are in three colors: red(R)…

BestCoder Round #25 1002 Harry And Magic Box [dp]

传送门 Harry And Magic Box Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 165 Accepted Submission(s): 64 Problem Description One day, Harry got a magical box. The box is made of n*m grids. Ther…

hihoCoder题目之Magic Box

#include <iostream> #include <cmath> #include <cstdio> using namespace std; void sort(int * a, int len)//冒泡升序排序 { int i, j, t; ;i < len-;i++) ;j < len--i;j++) ]) { t = a[j]; a[j] = a[j+]; a[j+] = t; } } int main() { freopen("i…

D. Magic Box（几何）

One day Vasya was going home when he saw a box lying on the road. The box can be represented as a rectangular parallelepiped. Vasya needed no time to realize that the box is special, as all its edges are parallel to the coordinate axes, one of its ve…

HDU 5155 Harry And Magic Box --DP

题意:nxm的棋盘,要求每行每列至少放一个棋子的方法数. 解法:首先可以明确是DP,这种行和列的DP很多时候都要一行一行的推过去,即至少枚举此行和前一行. dp[i][j]表示前 i 行有 j 列都有了棋子,且每行也有棋子. 这题做法: 从第1行到第n行,枚举这一行有k列已至少有一个,再枚举前一行有j列至少有一个,然后枚举这一行新放多少个棋子t,至少一个(因为每行至少一个) 那么有 dp[i][k] += dp[i-1][j]*C[m-j][k-j]*C[j][t-(k-j)], C表示组合数…

[HDOJ 5155] Harry And Magic Box

题目链接:HDOJ - 5155 题目大意有一个 n * m 的棋盘,已知每行每列都至少有一个棋子,求可能有多少种不同的棋子分布情况.答案对一个大素数取模. 题目分析算法1: 使用容斥原理与递推. 首先,一个 n * m 的棋盘不考虑任何限制时,可能的分布情况为 2^(n*m) ,除去没有棋子的情况,为 2^(n*m) - 1 . 然后,因为所有的 n 行,m 列都有棋子,所以枚举 ii (1 <= ii <= i) , jj (1 <= jj <= j) .对于枚举的一组 (…

【HDOJ】5155 Harry And Magic Box

DP.dp[i][j]可以表示i行j列满足要求的组合个数,考虑dp[i-1][k]满足条件,那么第i行的那k列可以为任意排列(2^k),其余的j-k列必须全为1,因此dp[i][j] += dp[i-1][k]*(2^k)*C(j, k). /* 5155 */ #include <cstdio> #include <cstring> #include <cstdlib> #define MAXN 51 ; __int64 dp[MAXN][MAXN]; __int64…

HDU-5155 Harry And Magic Box

题目描述在$n*m$的矩阵内每一行每一列都有钻石,问钻石分布的种类? 答案有可能很大,所以输出答案对$1000000007$取模. Input 对于每个测试用例,有两个整数$n$和$m$表示框的大小.$0< N,M<50$ Output 输出每组数据的分发数. Sample Input 1 1 2 2 2 3 Sample Output 1 7 25 这是一道比较优秀的容斥题. 首先,我们很显然的看到$n,m$范围都不是很大,考虑$dp$. 定义\(dp[i][j…

[Hdu-5155] Harry And Magic Box[思维题+容斥，计数Dp]

Online Judge:Hdu5155 Label:思维题+容斥,计数Dp 题面: 题目描述给定一个大小为$N*M$的神奇盒子,里面每行每列都至少有一个钻石,问可行的排列方案数.由于答案较大,输出对$1e9+7$取模后的结果. 输入多组数据.每组数据读入两个整数$N,M$ $0≤N,M≤50$ 输出每组数据输出一行表示答案. 样例 Input 1 1 2 2 2 3 Output 1 7 25 Hint There are 7 possible arrangements…

Harry And Magic Box HDU - 5155

题目链接:https://vjudge.net/problem/HDU-5155#author=0 题意:在一个n*m的方格中要满足每一行每一列至少有一个珠宝,问总共有多少种方案. 思路:利用递推的思想:dp[i][j]表示前i行前j列满足条件的个数,那么如果说前i行前j-1列已经满足条件了那么第j列可以放[1,n]个那么dp[i][j]=dp[i][j-1]*(2^n-1);因此假设前i行j-1列有k行还没放珠宝那么 dp[i][j]=dp[i-k][j-1]*C(i,k)*(C(i-k,0)…

微软往年校招招面试题AC全解。

因为4月初要参加微软的online.所以今天把微软的面试题拿出来做了,自己解答了题目.下面附上我的解答代码. -----------16年9月校招: 第一道题:Farthest Point(最远的整数点) 题目: #1237 : Farthest Point 时间限制:5000ms 单点时限:1000ms 内存限制:256MB 描述 Given a circle on a two-dimentional plane. Output the integral point in or on the…

Codeforces Round #143 (Div. 2)

A. Team 模拟. B. Magic, Wizardry and Wonders 可以发现\[d=a_1-a_2+a_3-a_4+\cdots\] 那么有$odd=\lfloor \frac{n+1}{2} \rfloor$个奇数,$even=\lfloor \frac{n}{2} \rfloor$个偶数. 奇数和范围为\[[max(odd,even+d), min(odd\cdot l, even\cdot l + d)]\] 判断有无解,有解则取均值分配下去即可. C. To A…

Codeforces Round #143 (Div. 2) (ABCD 思维场)

题目连链接:http://codeforces.com/contest/231 A. Team time limit per test:2 seconds memory limit per test:256 megabytes One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually…

Flink Event Time Processing and Watermarks（文末有翻译）

If you are building a Realtime streaming application, Event Time processing is one of the features that you will have to use sooner or later. Since in most of the real-world use cases messages arrive out-of-order, there should be some way through whi…

csu 1801(合数分解+排列组合)

1801: Mr. S’s Romance Time Limit: 1 Sec Memory Limit: 128 MBSubmit: 15 Solved: 5[Submit][Status][Web Board] Description Mr. S is a young math professor who is famous for being crazy about collecting prime numbers. Once he met a number, he would fir…

hdu 5155(递推)

Harry And Magic Box Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 624 Accepted Submission(s): 293 Problem Description One day, Harry got a magical box. The box is made of n*m grids. There a…

Code Project精彩系列（转）

Code Project精彩系列(转) Code Project精彩系列(转) Applications Crafting a C# forms Editor From scratch http://www.codeproject.com/csharp/SharpFormEditorDemo.asp 建立一个类似C#的环境, 实现控件拖拉,属性 Packet Capture and Analayzer 网络封包截获 http://www.codeproject.com/csharp/pa…

是的你没看错！！！用JAVA为MCU开发物联网程序?

是的你没看错!!!用JAVA为MCU开发物联网程序? 一直以来,物联网设备这种嵌入式硬件,对于Java软件开发者来说,就是Black Magic Box,什么中断.寄存器,什么指针.内存泄漏,什么五花八门的编译器.烧录软件——算了还是饶了我吧! 我们Java程序员要的是什么?我们要的是面向对象.是多线程.是框架.是GC.是免费好用的开发工具!嵌入式编程和Java程序员的距离,基本上就是哈利波特和钢铁侠——两个世界嘛! 不过,这两个世界在现在打…

【hihocoder 1499】A Box of Coins

[题目链接]:http://hihocoder.com/problemset/problem/1499 [题意] [题解] 贪心,模拟; 从左往右对于每一列; 如果上下两个格子; ① 有一个格子超过了所需; 另外一个格子小于所需; 则把超过了的格子转移一些到小于的那个,让上下两个互补; 然后把剩下的往右传(肯定是要往右传的); ② 如果两个格子都超过了所需; 则把两个格子多余的硬币都往右传. ③ 如果两个格子都小于所需; 则两个格子都从右边借一些 [Number Of WA] 1(输入是一列一列…

MAGIC XPA最新版本Magic xpa 2.4c Release Notes

New Features, Feature Enhancements and Behavior ChangesSubforms – Behavior Change for Unsupported Task ModeStarting with this version, if an Online task that is running in a Subform control cannot be executed, the task and the host task will remain o…

Magic xpa 2.5发布 Magic xpa 2.5 Release Notes

Magic xpa 2.5發佈 Magic xpa 2.5 Release Notes Magic xpa 2.5 Release NotesNew Features, Feature Enhancements and Behavior ChangesCall with Destination – Backward Compatibility EnhancementsIn Online, the following scenarios are now possible: Calling a p…

hihocoder #1052 基因工程

传送门:基因工程这道题拖了好久,一直没有清晰的思路. 当然,$K\le\frac{N}{2}$时,比较简单.下面我着重讲一下当$K>\frac{N}{2}$,即前$K$个字符与后$K$个字符有重叠时,如何思考这个问题. 为了便于分析,我们把题目要求形式化成如下的数学表示假设修改后的字符串为$S$,字符串长度为$N$,则$S$满足 \[S_i = S_{i+N-K} \qquad 1 \le i \le K \] 即“$S$是以$N-K$为周期的字符串”. 这样讲对吗?我们回忆一下数学上周…

Magic Quadrant for Security Information and Event Management

https://www.gartner.com/doc/reprints?id=1-4LC8PAW&ct=171130&st=sb Summary Security and risk management leaders are implementing and expanding SIEM to improve early targeted attack detection and response. Advanced users seek SIEM with advanced prof…

hihoCoder 1233 : Boxes（盒子）

hihoCoder #1233 : Boxes(盒子) 时间限制:1000ms 单点时限:1000ms 内存限制:256MB Description - 题目描述 There is a strange storehouse in PKU. In this storehouse there are n slots for boxes, forming a line. In each slot you can pile up any amount of boxes. The limitation i…