题目 题目链接 Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Example: Input: […

Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Example: Input: [4,3,2,7,…

https://leetcode.com/problems/find-all-duplicates-in-an-array/description/ 参考:http://www.cnblogs.com/grandyang/p/4843654.html Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all th…

后面3个题都是限制在1-n的,所有可以不先排序,可以利用巧方法做.最后两个题几乎一模一样. 217. Contains Duplicate class Solution { public: bool containsDuplicate(vector<int>& nums) { int length = nums.size(); ) return false; sort(nums.begin(),nums.end()); ;i < length;i++){ ]) return tr…

Question 442. Find All Duplicates in an Array Solution 题目大意:在数据中找重复两次的数 思路:数组排序,前一个与后一个相同的即为要找的数 Java实现: public List<Integer> findDuplicates(int[] nums) { List<Integer> ans = new ArrayList<>(); if (nums.length == 0) return ans; Arrays.so…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Follow up for "Remove Duplicates": What if duplicates are allowed at most twice? For example, Given sorted array nums = [1,1,1,2,2,3], Your function sho…

乘风破浪:LeetCode真题_026_Remove Duplicates from Sorted Array 一.前言     我们这次的实验是去除重复的有序数组元素,有大体两种算法. 二.Remove Duplicates from Sorted Array 2.1 问题      题目大意理解,就是对数组进行元素去重,然后返回去处重复之后的长度,无论我们对数组做了什么的修改,都没有关系的,只要保证再返回的长度之内的数组正确性即可.因为最后是根据长度来遍历的,因此我们不用担心. 2.2 分析…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 26: Remove Duplicates from Sorted Arrayhttps://oj.leetcode.com/problems/remove-duplicates-from-sorted-array/ Given a sorted array, remove the duplicates in place such that each element appe…

题目描述 给定一个整数数组 a,其中1 ≤ a[i] ≤ n (n为数组长度), 其中有些元素出现两次而其他元素出现一次. 找到所有出现两次的元素. 你可以不用到任何额外空间并在O(n)时间复杂度内解决这个问题吗? 示例: 输入: [4,3,2,7,8,2,3,1] 输出: [2,3] 思路 思路一: 直接利用hashmap记录出现次数 思路二: 因为数组输入的特点 1<=a[i]<=n,则可以把原数组当hash表用 ,因为原数组是正数,标为负数表示出现过,如果遇到负数就表示第二次出现,就可以…

https://leetcode.com/problems/remove-duplicates-from-sorted-array/ Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this…