HDU 4617 Weapon(三维几何)】的更多相关文章

题意:给你一些无限长的圆柱,知道圆柱轴心直线(根据他给的三个点确定的平面求法向量即可)与半径,判断是否有圆柱相交.如果没有,输出柱面最小距离. 一共只有30个圆柱,直接暴力一下就行. 判相交/相切:空间直线距离是否小于等于两圆柱半径和若无相交,求最小:空间直线距离-两圆柱半径和 #include <cstdio> #include <cstdlib> #include <cstring> #include <algorithm> #include <c…
链接: http://acm.hdu.edu.cn/showproblem.php?pid=4617 Weapon Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others) Total Submission(s): 224    Accepted Submission(s): 178 Problem Description Doctor D. are researching for a…
http://acm.hdu.edu.cn/showproblem.php?pid=4617 三维几何简单题 多谢高尚博学长留下的模板 代码: #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> using namespace std; typedef long long ll; typedef pair<…
Problem Description Doctor D. are researching for a horrific weapon. The muzzle of the weapon is a circle. When it fires, rays form a cylinder that runs through the circle verticality in both side. If one cylinder of rays touch another, there will be…
Weapon Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 22    Accepted Submission(s): 18 Problem Description Doctor D. are researching for a horrific weapon. The muzzle of the weapon is a circle.…
大一学弟表示刚学过高数,轻松无压力. 我等学长情何以堪= = 求空间无限延伸的两个圆柱体是否相交,其实就是叉积搞一搞 详细点就是求两圆心的向量在两直线(圆心所在的直线)叉积上的投影 代码略挫,看他的吧http://blog.csdn.net/liuledidai/article/details/9494363…
Special Tetrahedron Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 328    Accepted Submission(s): 130 Problem Description Given n points which are in three-dimensional space(without repetition)…
Ultimate Weapon Time Limit: 2000MS   Memory Limit: 131072K Total Submissions: 2430   Accepted: 1173 Description In year 2008 of the Cosmic Calendar, the Aliens send a huge armada towards the Earth seeking after conquest. The humans now depend on thei…
HDU - 3584 Cube Time Limit: 1000MS   Memory Limit: 65536KB   64bit IO Format: %I64d & %I64u Submit Status Description Given an N*N*N cube A, whose elements are either 0 or 1. A[i, j, k] means the number in the i-th row , j-th column and k-th layer. I…
题意:给一个三维数组n*n*n,初始都为0,每次有两个操作: 1. 翻转(x1,y1,z1) -> (x2,y2,z2) 0. 查询A[x][y][z] (A为该数组) 解法:树状数组维护操作次数,一个数被操作偶数次则相当于没被操作. 每次更新时在8个位置更新: .相当于8个二进制数:000,001,010,011,100,101,110,111. (我是由二维推过来的) 其实不用有的为-1,直接1也行,因为反正会改变奇偶性. 代码: #include <iostream> #inclu…