In a deck of cards, each card has an integer written on it. Return true if and only if you can choose X >= 2 such that it is possible to split the entire deck into 1 or more groups of cards, where: Each group has exactly X cards. All the cards in eac…

原题 题目原意可转换为 两组有大于等于2的公因数 /** * @param {number[]} deck * @return {boolean} */ var hasGroupsSizeX = function(deck) { var map = {}; for (let i = 0; i < deck.length; i++) { if (map[deck[i]]) map[deck[i]] += 1; else map[deck[i]] = 1; } var min = map[deck[…

problem 914. X of a Kind in a Deck of Cards 题意:每个数字对应的数目可以均分为多组含有K个相同数目该数字的数组. 思路:使用 map 结构记录数组中每个元素出现的次数,该题转化为求次数的最大公约数,若所有次数的最大公约数大于或者等于 2,返回 true,否则返回 false. solution: class Solution { public: bool hasGroupsSizeX(vector<int>& deck) { //Greate…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 遍历 最大公约数 日期 题目地址: https://leetcode.com/problems/x-of-a-kind-in-a-deck-of-cards/description/ 题目描述 In a deck of cards, each card has an integer written on it. Return true if and…

In a deck of cards, each card has an integer written on it. Return true if and only if you can choose X >= 2 such that it is possible to split the entire deck into 1 or more groups of cards, where: Each group has exactly X cards. All the cards in eac…

这是悦乐书的第352次更新,第377篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第214题(顺位题号是914).在一副牌中,每张牌上都写有一个整数. 当且仅当您可以选择X >= 2时才返回true,以便可以将整个牌组分成一组或多组牌,其中: 每组都有X张牌. 每组中的所有牌都具有相同的整数. 例如: 输入:[1,2,3,4,4,3,2,1] 输出:true 说明:可能的分区[1,1],[2,2],[3,3],[4,4] 输入:[1,1,1,2,2,2,3,3] 输…

In a deck of cards, each card has an integer written on it. Return true if and only if you can choose X >= 2 such that it is possible to split the entire deck into 1 or more groups of cards, where: Each group has exactly X cards. All the cards in eac…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

第950题,这题我是真的没想到居然会说使用队列去做,大神的答案,拿过来瞻仰一下 package y2019.Algorithm.array; import java.util.HashMap; import java.util.Map; /** * @ClassName Exist * @Description TODO 79. Word Search * * Given a 2D board and a word, find if the word exists in the grid. *…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 把自己刷过的所有题目做一个整理,并且用简洁的语言概括了一下思路,汇总成了一个表格. 题目的排列顺序是按照先Easy再Medium再Hard排列的,暂时还没有把题目全部整理完成.后序我会把刷过的所有的题目都整理到这个文档里. 题目 难度 解法 题目地址 566. Reshape the Matrix Easy 变长数组,求余法,维护行列计算在新的数组中的位置 https://blog.c…