#include<iostream> using namespace std; struct { int a; double b; }poly[1001]; double a[2001];//至少2000个位置 int main(){ int n,m,cnt=0,aa; double bb; cin>>n; for(int i=0;i<n;i++){ cin>>poly[i].a>>poly[i].b; } cin>>m; for(int…

1009 Product of Polynomials (25分)   This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polyno…

题目 This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​ ​​ N​2​​ a​…

This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​​​ N​2​​ a​N​2​…

题意: 给出两个多项式,计算两个多项式的积,并以指数从大到小输出多项式的指数个数,指数和系数. trick: 这道题数据未知,导致测试的时候发现不了问题所在. 用set统计非零项时,通过set.size()输出非零项个数,set.count()与否来判断是否输出该项时结果第0个测试点答案错误. 用fabs(mp[i])>=0.05时结果全部正确,因为考虑到保留1位小数所以用这个语句来判断保留小数后是否非零. 问题是当去掉fabs()时采用mp[i]>=0.05结果第0个测试点答案错误. 而不管…

1009 Product of Polynomials (25)(25 分) This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a pol…

1009. Product of Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case oc…

1009. Product of Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case oc…

1009. Product of Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case oc…

题目链接:http://pat.zju.edu.cn/contests/pat-a-practise/1009 分析:简单题.相乘时指数相加,系数相乘即可,输出时按指数从高到低的顺序.注意点:多项式相乘后指数最高可达2000. 题目描述: This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test…

This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, wh…

problem This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 a~N1~ N2 a~N2~ ..…

#include <stdio.h> struct MyStruct { int exp; double coe; }; int main() { int k1,k2,i,j; MyStruct ans1[],ans2[]; ]; //两个 最高幂相乘 , 最高幂为2000 while(scanf("%d",&k1)!=EOF) { ;i<=;i++) dans[i]=0.0; ;i<k1;i++) scanf("%d%lf",&am…

简单模拟. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> using namespace std; ],b[],c[]; int k; int main() { ;i<=;i++) a[i]=b[i]=c[i]=; ; scanf("%d",&k); ;i<=k;i++) {…

多项式相乘 注意相乘结果的多项式要开两倍的大小!!! #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <string.h> using namespace std; //两个多项式相乘 +; int k; //原本定义个exp导致编译错误,没想到定义成exp1.exp2也会编译错误,估计引起函数名冲突了 double ex…

1009. Product of Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case oc…

1009 Product of Polynomials (25 分) This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynom…

A1009 Product of Polynomials (25)(25 分) This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a po…

1009 Product of Polynomials (25 分)   This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polyn…

1009 Product of Polynomials This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K …

1002 A+B for Polynomials (25分)   This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomia…

PAT (Advanced Level) Practice 1002 A+B for Polynomials (25 分) 凌宸1642 题目描述: This time, you are supposed to find A+B where A and B are two polynomials. 译:这一次,你要找到 A + B ,其中 A , B 是两个多项式 Input Specification (输入说明): Each input file contains one test case…

PATA1009 Product of Polynomials Output Specification: For each test case you should output the product of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate up…

This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 … NK aNK, wher…

题意:模拟多项式相乘 思路:略.有一个注意点,题目中说指数最大为1000,当两个多项式相乘后,指数最大就为2000,这一点不注意会出现段错误. 代码: #include <cstdio> ;//注意N必须大于等于2000,而不能是1000 struct Term{ double coe;//系数 int exp;//指数 }a[],b[]; int main() { //freopen("pat.txt","r",stdin); int ka,kb; s…

课本AC代码 #include <cstdio> struct Poly { int exp;//指数 double cof; } poly[1001];//第一个多项式 double ans[2001];//存放结果 int main() { #ifdef ONLINE_JUDGE #else freopen("1.txt", "r", stdin); #endif // ONLINE_JUDGE int n, m, number = 0; scanf…

This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​​​ N​2​​ a​N​2​…

题目 This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​ ​​ N​2​​ a​…

This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​​​ N​2​​ a​N​2​…

参考:https://www.jianshu.com/p/e7a3ee0f82d9 #include<bits/stdc++.h> using namespace std; ; double xi[N]; struct node { int zhi;//指数 double xi;//系数 }noa[],nob[]; int main() { int na,nb; cin>>na; ;i<na;i++) { cin>>noa[i].zhi; cin>>n…