LeetCode382-链表随机节点】的更多相关文章

Given a singly linked list, return a random node's value from the linked list. Each node must have the same probability of being chosen. Follow up:What if the linked list is extremely large and its length is unknown to you? Could you solve this effic…
382. 链表随机节点 给定一个单链表,随机选择链表的一个节点,并返回相应的节点值.保证每个节点被选的概率一样. 进阶: 如果链表十分大且长度未知,如何解决这个问题?你能否使用常数级空间复杂度实现? 示例: // 初始化一个单链表 [1,2,3]. ListNode head = new ListNode(1); head.next = new ListNode(2); head.next.next = new ListNode(3); Solution solution = new Solut…
Given a singly linked list, return a random node's value from the linked list. Each node must have the same probability of being chosen. Follow up: What if the linked list is extremely large and its length is unknown to you? Could you solve this effi…
给定一个单链表,随机选择链表的一个节点,并返回相应的节点值.保证每个节点被选的概率一样.进阶:如果链表十分大且长度未知,如何解决这个问题?你能否使用常数级空间复杂度实现?示例:// 初始化一个单链表 [1,2,3].ListNode head = new ListNode(1);head.next = new ListNode(2);head.next.next = new ListNode(3);Solution solution = new Solution(head);// getRand…
Given a singly linked list, return a random node's value from the linked list. Each node must have the same probability of being chosen. Follow up: What if the linked list is extremely large and its length is unknown to you? Could you solve this effi…
原题链接:[382. 链表随机节点]:https://leetcode-cn.com/problems/linked-list-random-node/ 题目描述: 给定一个单链表,随机选择链表的一个节点,并返回相应的节点值.保证每个节点被选的概率一样. 进阶: 如果链表十分大且长度未知,如何解决这个问题?你能否使用常数级空间复杂度实现? 示例: // 初始化一个单链表 [1,2,3]. ListNode head = new ListNode(1); head.next = new ListN…
2.3 Implement an algorithm to delete a node in the middle of a singly linked list, given only access to that node.EXAMPLEInput: the node c from the linked list a->b->c->d->eResult: nothing is returned, but the new linked list looks like a- >…
/** * 在O(1)的时间删除链表的节点 * * @author * */ public class Solution { public static void deleteNode(Node head, Node deletedNode) { if (null == head || null == deletedNode) { return; } if (deletedNode.next != null) { // 删除的不是尾节点 System.out.println("1-----&qu…
剑指Offer:删除链表的节点[18] 题目描述 在一个排序的链表中,存在重复的结点,请删除该链表中重复的结点,重复的结点不保留,返回链表头指针. 例如,链表1->2->3->3->4->4->5 处理后为 1->2->5 题目分析 如上图所示,我们的定义了三个指针,其中第二.三个指针用于找到重复元素的第一个位置和最后一个位置的下一个位置,然后第一个指针的下一个指向三个指针,这样就跳过了重复元素. 但是编码发现后,还有两种情况欠考虑. 这种情况,刚开始,就是…
题目描述 输入一个链表,从尾到头打印链表每个节点的值. 思路1. 翻转链表,使用java自带的翻转函数或者从头到尾依次改变链表的节点指针 /** * public class ListNode { * int val; * ListNode next = null; * * ListNode(int val) { * this.val = val; * } * } * */ import java.util.ArrayList; import java.util.Collections; pub…