50. Plus One-Leetcode - 相关文章

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[Leetcode][Python]50: Pow(x, n)

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 50: Pow(x, n)https://leetcode.com/problems/powx-n/ Implement pow(x, n). === Comments by Dabay===技巧在于用x的平方来让n减半.同时注意n为负数的情况,以及n为奇数的情况.''' class Solution: # @param x, a float # @param n, a in…

LeetCode解题录-1~50

[leetcode]1. Two Sum两数之和 Two Pointers, HashMap Easy [leetcode]2. Add Two Numbers两数相加 Math, LinkedList Medium [leetcode]3. Longest Substring Without Repeating Characters无重复字母的最长子串 Sliding Window Medium [leetcode]4. Median of Two Sorted Arrays俩有序数组的中位数…

[LeetCode] 50. Pow(x, n) 求x的n次方

Implement pow(x, n), which calculates x raised to the power n(xn). Example 1: Input: 2.00000, 10 Output: 1024.00000 Example 2: Input: 2.10000, 3 Output: 9.26100 Example 3: Input: 2.00000, -2 Output: 0.25000 Explanation: 2-2 = 1/22 = 1/4 = 0.25 Note:…

LeetCode 50. Pow(x, n) 12

50. Pow(x, n) 题目描述实现 pow(x, n),即计算 x 的 n 次幂函数. 每日一算法2019/5/15Day 12LeetCode50. Pow(x, n) 示例 1: 输入: 2.00000, 10 输出: 1024.00000 示例 2: 输入: 2.10000, 3 输出: 9.26100 示例 3: 输入: 2.00000, -2 输出: 0.25000 解释: 2-2 = 1/22 = 1/4 = 0.25 说明: -100.0 < x < 100.0 n 是…

LeetCode - 50. Pow(x, n)

50. Pow(x, n) Problem's Link ---------------------------------------------------------------------------- Mean: 略. analyse: 快速幂. Time complexity: O(N) view code ; ) ; ) ,n*=n; } return ans; }};…

50. leetcode 520. Detect Capital

520. Detect Capital Given a word, you need to judge whether the usage of capitals in it is right or not. We define the usage of capitals in a word to be right when one of the following cases holds: All letters in this word are capitals, like "USA&quo…