单词搜索 II · Word Search II】的更多相关文章

Leetcode之回溯法专题-79. 单词搜索(Word Search) 给定一个二维网格和一个单词,找出该单词是否存在于网格中. 单词必须按照字母顺序,通过相邻的单元格内的字母构成,其中“相邻”单元格是那些水平相邻或垂直相邻的单元格.同一个单元格内的字母不允许被重复使用. 示例: board = [ ['A','B','C','E'], ['S','F','C','S'], ['A','D','E','E'] ] 给定 word = "ABCCED", 返回 true. 给定 wor…
Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same le…
[抄题]: 给出一个由小写字母组成的矩阵和一个字典.找出所有同时在字典和矩阵中出现的单词.一个单词可以从矩阵中的任意位置开始,可以向左/右/上/下四个相邻方向移动. 给出矩阵: doafagaidcan 和字典: {"dog", "dad", "dgdg", "can", "again"}   返回 {"dog", "dad", "can", &q…
题目描述 给定一个二维网格和一个单词,找出该单词是否存在于网格中. 单词必须按照字母顺序,通过相邻的单元格内的字母构成,其中“相邻”单元格是那些水平相邻或垂直相邻的单元格.同一个单元格内的字母不允许被重复使用. 示例: board = [ ['A','B','C','E'], ['S','F','C','S'], ['A','D','E','E'] ] 给定 word = "ABCCED", 返回 true. 给定 word = "SEE", 返回 true. 给定…
Leetcode之回溯法专题-212. 单词搜索 II(Word Search II) 给定一个二维网格 board 和一个字典中的单词列表 words,找出所有同时在二维网格和字典中出现的单词. 单词必须按照字母顺序,通过相邻的单元格内的字母构成,其中“相邻”单元格是那些水平相邻或垂直相邻的单元格.同一个单元格内的字母在一个单词中不允许被重复使用. 示例: 输入: words = ["oath","pea","eat","rain&q…
https://www.cnblogs.com/grandyang/p/4332313.html 在一个矩阵中能不能找到string的一条路径 这个题使用的是dfs.但这个题与number of islands有点不同,那个题中visited过的就不用再扫了,但是这个需要进行回溯回来. 所以使用了visited[i][j] = false; 本质区别还是那个题是找一片区域,这个题更像是找一条路径. 错误一:如果board不引用,会报超内存 错误二: 这个写法和正确写法基本相同,但错误写法需要每次…
Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same le…
Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same le…
Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same le…
Given an m x n board of characters and a list of strings words, return all words on the board. Each word must be constructed from letters of sequentially adjacent cells, where adjacent cells are horizontally or vertically neighboring. The same letter…
题目: Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The sam…
Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same le…
Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same le…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 前缀树 日期 题目地址:https://leetcode.com/problems/word-search-ii/ 题目描述 Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be construc…
https://leetcode.com/problems/word-search-ii/description/ Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are…
单词拆分2,递归+dp, 需要使用递归,同时使用记忆化搜索保存下来结果,c++代码如下 class Solution { public: //定义一个子串和子串拆分(如果有的话)的映射 unordered_map<string,vector<string>>m; vector<string> wordBreak(string s, vector<string>& wordDict) { if(m.count(s)) return m[s];//当映射…
Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same le…
超时,用了tire也不行,需要再改. class Solution { class TrieNode { public: // Initialize your data structure here. TrieNode() { for(int i=0;i<26;i++) next[i]=NULL; isString = false; } TrieNode *next[26]; bool isString; }; class Trie { public: Trie() { root = new T…
Problem: Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. Th…
Question Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. Th…
Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each transformed word must exist in the word list. Note…
Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences. Note: The same word in the dictionary m…
Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same le…
https://leetcode.com/problems/word-search/ class Solution { public: struct Trie{ Trie *next[]; bool isWord; Trie() { this->isWord = false; for(auto &c: next) c = NULL; } }; void insert(Trie *root, string word) { Trie *p = root; for(auto &c: wor…
Given a pattern and a string str, find if strfollows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty substring in str. Example 1: Input: pattern = "abab", str = "r…
Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be us…
Word Search I Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell…
Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be us…
79. Word Search Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter ce…
Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be us…