HDU 4403 A very hard Aoshu problem】的更多相关文章

A very hard Aoshu problem Problem Description Aoshu is very popular among primary school students. It is mathematics, but much harder than ordinary mathematics for primary school students. Teacher Liu is an Aoshu teacher. He just comes out with a pro…
http://acm.hdu.edu.cn/showproblem.php?pid=4403 题意: 给出一串数字,在里面添加一个等号和多个+号,使得等式成立,问有多少种不同的式子. 思路: 数据量比较小,直接dfs爆搜答案即可. #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<map> using namespace std;…
暴力$dfs$. 先看数据范围,字符串最长只有$15$,也就是说枚举每个字符后面是否放置“$+$”号的复杂度为${2^{15}}$. 每次枚举到一种情况,看哪些位置能放“$=$”号,每个位置都试一下,然后判断一下是否可行. 最坏复杂度$O({2^{15}}*{15^2})$,事实上是达不到最坏复杂度的. #pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<c…
题意:给你一个数字字符串.问在字符串中间加'='.'+'使得'='左右两边相等. 1212  : 1+2=1+2,   12=12. 12345666 : 12+3+45+6=66.  1+2+3+4+56=66: #include<stdio.h> #include<string.h> #include<string> #include<map> #include<stack> #include<math.h> #include&l…
HASH+暴力. /* 4403 */ #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <map> using namespace std; #define MAXN 55 map<]; char s[MAXN]; int get(int b, int e) { ; for (int i=b; i<e; ++i)…
题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=4403 A very hard Aoshu problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1080    Accepted Submission(s): 742 Problem Description Aoshu is ver…
Description Math Olympiad is called “Aoshu” in China. Aoshu is very popular in elementary schools. Nowadays, Aoshu is getting more and more difficult. Here is a classic Aoshu problem: ABBDE __ ABCCC = BDBDE In the equation above, a letter stands for…
Description Math Olympiad is called “Aoshu” in China. Aoshu is very popular in elementary schools. Nowadays, Aoshu is getting more and more difficult. Here is a classic Aoshu problem: ABBDE __ ABCCC = BDBDEIn the equation above, a letter stands for a…
pid=4972" target="_blank" style="">题目链接:hdu 4972 A simple dynamic programming problem 题目大意:两支球队进行篮球比赛,每进一次球后更新比分牌,比分牌的计数方法是记录两队比分差的绝对值,每次进球的分可能是1,2,3分. 给定比赛中的计分情况.问说最后比分有多少种情况. 解题思路:分类讨论: 相邻计分为1-2或者2-1的时候,会相应有两种的的分情况 相邻计分之差大于3或…
A very hard Aoshu problem                           Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description Aoshu is very popular among primary school students. It is mathematics, but much harder than o…