PAT甲级——1108.Finding Average (20分)】的更多相关文章

The basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A legal input is a real number in [−1000,1000] and is accurate up to no m…
The basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A legal input is a real number in [−] and is accurate up to no more than…
话不多说: 该题要求将给定的所有数分为两类,其中这两类的个数差距最小,且这两类分别的和差距最大. 可以发现,针对第一个要求,个数差距最小,当给定个数为偶数时,二分即差距为0,最小:若给定个数为奇数时,差距为1时最小. 针对第二个要求:则将所有给定的数从小到大排列,将前半部分给那个和小些的集合,其余给那个和大的集合,这样做和差距会最大. 以此思路编写代码如下: #include<cstdio> #include<iostream> #include<algorithm>…
题意: 输入一个正整数N(<=100),接着输入一行N组字符串,表示一个数字,如果这个数字大于1000或者小于1000或者小数点后超过两位或者压根不是数字均为非法,计算合法数字的平均数. trick: 测试点2答案错误原因:题面指出如果只有一个合法数字,输出numbers的时候不加s,即为number. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std;…
1035 Password (20 分) To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) fr…
1073 Scientific Notation (20 分)   Scientific notation is the way that scientists easily handle very large numbers or very small numbers. The notation matches the regular expression [+-][1-9].[0-9]+E[+-][0-9]+ which means that the integer portion has…
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