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题目描述 http://codeforces.com/contest/1339/problem/B 有一个长度为 \(n(3\le n \le 10^5)\) 的整数序列 \(a_1,a_2,...,a_n(-10^9\le a_i\le 10^9)\) . 将序列重排序使得 \(|a_1-a_2|\le|a_2-a_3|\le...\le|a_{n-1}-a_n|\) . 输出任意一种满足上述条件的排序方式. 解题 这里采用一种类似贪心的策略: 序列 \(a\) 中的最大值与最小值差的绝对值(…
B - Sorted Adjacent Differences(CodeForces - 1339B) 题目链接 算法 思维+贪心 时间复杂度O(nlogn) 1.这道题的题意主要就是让你对一个数组进行一种特殊的排序,使得数组中相邻的两个数的差的绝对值成非递减趋势: 2.刚开始对这道题总是执拗于两个相等的数在不同位置,如何把它们放到前面这个问题,因为路走歪了,最终无果,没有思路.后来看了一些关于这道题的解题博客,豁然开朗. 3.使得数组中相邻的两个数的差的绝对值成非递减趋势,怎么想呢.单纯想怎么…
\(给出n个数字,要求构造一个由这n个数组成的序列,使得|a_1-a_2|<=|a_2-a_3|...<=|a_{n-1}-a_n|\) \(排序后,从数列中间取个数,然后从左右分别循环取数,这样保证差值递增\) \(还是很巧妙地.\) #include <bits/stdc++.h> using namespace std; int t,n,a[100009]; int main() { cin>>t; while(t--) { cin>>n; for(i…
Educational Codeforces Round 37 (Rated for Div. 2)C. Swap Adjacent Elements time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You have an array a consisting of n integers. Each integer from 1…
题目描述 http://codeforces.com/contest/1339/problem/A 给定一个 \(n(1\le n \le 10^9)\) ,问用一个由两个三角形组成的菱形,填充下面这种图形有多少种不同的填法. 解题 通过枚举发现,被填充图形中竖着的菱形区域正好是 \(n\) 个. 而且在任何一种填充方式中,只能同时存在一个竖着的菱形填充,其余的填充必须是横向的菱形. 选取不同的竖向菱形区块填充,最终也都只能得到一种不同的填充方式. 所以填充方式数目 \(ans = n\) .…
题目描述 http://codeforces.com/contest/1339/problem/C 给定一个长度为 \(n\) 的无序数组,你可以在第 \(x\) 秒进行一次下面的操作. 从数组选取任意个数字(也可以一个都不选),为他们全部都加上 \(2^{x-1}\) . 询问你最少可以用多少秒,使得数组非降序排列. 解题 最快策略 首先简化一下问题,假设操作变成:第 \(x\) 秒,可以选取任意个数字,为他们全部都加上 \(1\) .分析一下在这个条件下,可以达到最少秒数的策略. 假设我们有…
地址 Problem - C - Codeforces 题意 每个格子,该格子和相邻的格子的值不能相同 题解 思维题, 先从1~n输出奇数,再输出偶数 代码 #include <iostream> #include <string> #include <algorithm> using namespace std; typedef long long LL; int a[110][110]; int main() { LL n, t; cin >> t; w…
Codeforces Round #633(Div.2) \(A.Filling\ Diamonds\) 答案就是构成的六边形数量+1 //#pragma GCC optimize("O3") //#pragma comment(linker, "/STACK:1024000000,1024000000") #include<bits/stdc++.h> using namespace std; function<void(void)> __…
A. Filling Diamonds 题意:给你n个菱形方块,问能构成图示形状的有多少种 题解:自己画几个不难发现答案是n 代码: 1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #include <cmath> 5 #include <algorithm> 6 #include <stack> 7 #include <queue> 8 #…
title: woj1019 Curriculum Schedule 输入输出 date: 2020-03-19 10:43:00 categories: acm tags: [acm,woj] 水题,处理好输入输出就可以 1 描述 New semester has begun, a lot of students are going to print out their curriculum schedules. They are using the same template, as the…
1 在JSX的元素中写入内联样式,例如<div style={"color:blue"}></div> 报错:warning:Style prop value must be an object  react/style-prop-object 原因:在React框架的JSX编码格式要求,style必须是一个对象 解决方法:除了外部那个表示Javascript语句的花括号外,里面必须再写一个花括号{}包含的对象,例如<div style={ {  colo…
http://codeforces.com/contest/1006/problem/A Mishka got an integer array aa of length nn as a birthday present (what a surprise!). Mishka doesn't like this present and wants to change it somehow. He has invented an algorithm and called it "Mishka's A…
http://codeforces.com/contest/876/problem/B 题意: 给出n个数,要求从里面选出k个数使得这k个数中任意两个的差能够被m整除,若不能则输出no. 思路: 差能够被m整除,其实就是对m取余的余数相同.那么就统计n个数的余数丢到一个map里面,最后判断是否有某个数的数量大于等于k. 代码: #include <stdio.h> #include <map> #include <vector> using namespace std;…
题意: 给你一个由小写字母组成的字符串,若串中两个相邻元素字典序中也相邻,移除较大字母,问最多能移除多少个字母. 思路: 从大到小依次枚举. Tips: 注意下标的处理. 以小消大: #include <bits/stdc++.h> using namespace std; int main() { int n;cin>>n; string s;cin>>s; int ans=0; for(char c='y';c>='a';c--){ for(int i=0;i…
D. Jeff and Furik time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Jeff has become friends with Furik. Now these two are going to play one quite amusing game. At the beginning of the game Je…
Hard problem 题目链接: http://codeforces.com/contest/706/problem/C Description Vasiliy is fond of solving different tasks. Today he found one he wasn't able to solve himself, so he asks you to help. Vasiliy is given n strings consisting of lowercase Engl…
D. Bubble Sort Graph time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Iahub recently has learned Bubble Sort, an algorithm that is used to sort a permutation with n elements a1, a2, ..., an …
A. Sea Battle time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output In order to make the "Sea Battle" game more interesting, Boris decided to add a new ship type to it. The ship consists of…
E - Sorted and Sorted Time limit : 2sec / Memory limit : 1024MB Score : 600 points Problem Statement There are 2N balls, N white and N black, arranged in a row. The integers from 1 through N are written on the white balls, one on each ball, and they…
Codeforces Round #486 (Div. 3) E. Divisibility by 25 题目连接: http://codeforces.com/group/T0ITBvoeEx/contest/988/problem/E Description You are given an integer n from 1 to 10^18 without leading zeroes. In one move you can swap any two adjacent digits in…
Codeforces Round #486 (Div. 3) D. Points and Powers of Two 题目连接: http://codeforces.com/group/T0ITBvoeEx/contest/988/problem/D Description There are n distinct points on a coordinate line, the coordinate of i-th point equals to xi. Choose a subset of…
一.sorted面试题 面试题: [11, 33, 4, 2, 11, 4, 9, 2] 去重并保持原来的顺序 答案1: list1 = [11, 33, 4, 2, 11, 4, 9, 2] ret = set(list1) list2 = [] for i in list1: if i not in list2: list2.append(i) print(list2) 执行输出:[11, 33, 4, 2, 9] 答案2: list1 = [11, 33, 4, 2, 11, 4, 9,…
题面 B - Moderate Differences Time limit : 2sec / Memory limit : 256MB Score : 400 points Problem Statement There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.…
A. Vladik and Courtesy 题面 At regular competition Vladik and Valera won a and b candies respectively. Vladik offered 1 his candy to Valera. After that Valera gave Vladik 2 his candies, so that no one thought that he was less generous. Vladik for same…
http://codeforces.com/contest/351/problem/B 题意: 给出一个n的排列 第一个人任选两个相邻数交换位置 第二个人有一半的概率交换相邻的第一个数>第二个数的位置:有一半的概率交换相邻第一个数<第二个数的位置 然后两人轮换 问使序列升序,期望最少操作次数 序列升序即逆序对数为0 dp[i]表示 当前逆序对还剩i对时,先手期望最少操作次数 先手在最优解的情况下一定交换 第一个数>第二个数的位置,即减少1个逆序对 后手等概率增加或减少1个逆序对 dp[i…
Abstract "HTML5 Differences from HTML4" describes the differences of the HTML5 specification from those of HTML4. Status of This Document This section describes the status of this document at the time of its publication. Other documents may supe…
Codeforces Round #297 (Div. 2)D. Arthur and Walls Time Limit: 2 Sec  Memory Limit: 512 MBSubmit: xxx  Solved: 2xx 题目连接 http://codeforces.com/contest/525/problem/D Description Finally it is a day when Arthur has enough money for buying an apartment. H…
Codeforces Round #441 (Div. 2) codeforces 876 A. Trip For Meal(水题) 题意:R.O.E三点互连,给出任意两点间距离,你在R点,每次只能去相邻点,要走过n个点,求走过的最短距离. #include<cstdio> #include<cstring> #include<algorithm> using namespace std; int main() { int n, a, b, c; scanf("…
Codeforces Round #441 (Div. 2) A. Trip For Meal 题目描述:给出\(3\)个点,以及任意两个点之间的距离,求从\(1\)个点出发,再走\(n-1\)个点的最短路径. solution 当\(n=1\)时,答案为\(0\),当\(n=2\)时,答案等于与开始点相连的两条边的最小值,当\(n>2\)时,答案等于与开始点相连的两条边的最小值+三条边最小值*\((n-2)\) 时间复杂度:\(O(1)\) B. Divisiblity of Differen…
A. Minimum Binary Number time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output String can be called correct if it consists of characters "0" and "1" and there are no redundant lead…