Tricks Device (hdu 5294 最短路+最大流)

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Tricks Device (hdu 5294 最短路+最大流)

Tricks Device Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 124 Accepted Submission(s): 27 Problem Description Innocent Wu follows Dumb Zhang into a ancient tomb. Innocent Wu's at the entr…

hdu 5294 最短路+最大流 ***

处理处最短路径图,这个比较巧妙链接:点我…

HDU 5294 Tricks Device（多校2015 最大流+最短路啊）

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5294 Problem Description Innocent Wu follows Dumb Zhang into a ancient tomb. Innocent Wu's at the entrance of the tomb while Dumb Zhang's at the end of it. The tomb is made up of many chambers, the total…

hdu 3599(最短路+最大流）

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3599 思路:首先spfa求一下最短路,然后对于满足最短路上的边(dist[v]==dist[u]+w)加入到新图中来,边容量为1,最后求出的最大流就是没有相交的边的最短路径条数. #include<iostream> #include<cstdio> #include<string> #include<algorithm> #include<vector&…

HDU 5294 Tricks Device (最大流+最短路)

题目链接:HDU 5294 Tricks Device 题意:n个点,m条边.而且一个人从1走到n仅仅会走1到n的最短路径.问至少破坏几条边使原图的最短路不存在.最多破坏几条边使原图的最短路劲仍存在思路: 1.跑一遍最短路.记录下全部最短路径,将这些最短路径的边以(0,1)(流量,容量)加到网络流中,跑一遍最大流 2.记录下的全部最短路径,再加到新的最短路的图中,边权为1,跑一遍最短路.m-最短路就是答案注意:有重边的情况比方: 2 3 1 2 1 1 2 1 1 2 1 ans: 3…

hdu 5294 Tricks Device 最短路建图+最小割

链接:http://acm.hdu.edu.cn/showproblem.php?pid=5294 Tricks Device Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 375 Accepted Submission(s): 98 Problem Description Innocent Wu follows Dumb Zh…

HDU 5294 Tricks Device 网络流最短路

Tricks Device 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5294 Description Innocent Wu follows Dumb Zhang into a ancient tomb. Innocent Wu's at the entrance of the tomb while Dumb Zhang's at the end of it. The tomb is made up of many chambers, th…