http://acm.hdu.edu.cn/showproblem.php?pid=5095 就是把ax^2 + by^2 + cy^2 + dxy + eyz + fzx + gx + hy + iz + j转换成ap + bq + cr + du + ev + fw + gx + hy + iz + j 注意的地方就是开头不要有+,系数为0不输出,系数为1的话不能输出系数除非指数为0等等 #include <cstdio> #include <cstdlib> #include…

关键在排序!!! 数组间的排序会超时,所以需要把一个数组映射成一个数字,就可以了 #include <bits/stdc++.h> using namespace std; typedef long long ll; const int maxn = 1e5 + 5; const ll Mod = 1e9 + 7; int len,ltt[26][maxn]; char s[maxn]; bool apr[26]; ll pow26[maxn]; void init() { int len =…

[NOI2013模拟]坑带的树 题意: 求\(n\)个点,\(m\)条边的同构仙人球个数. \(n\le 1000\) 这是一道怎么看怎么不可做的题. 这种题,肯定是圆方树啦~ 好,那么首先转为广义圆方树. 圆方树上有两种点(废话),那么对于一个方点,它实际上代表的是一个点双,所以我们需要判断一个方点的子树是否中间对称,如果对称则这个子树答案乘\(2\). 显然. 然后判断一个圆点与几个方点相连时,注意到方点之间是可以互相交换顺序的,于是我们看看有多少个子树相同,乘个阶乘. 最后就是求同构仙人球…

主题链接:http://acm.hdu.edu.cn/showproblem.php? pid=5095 Problem Description SVM(Support Vector Machine)is an important classification tool, which has a wide range of applications in cluster analysis, community division and so on. SVM The kernel function…

描述 一元 n 次多项式可用如下的表达式表示:  f(x)=an*x^n+an-1*x^n-1+...+a1*x+a0,an<>0其中,ai*a^x 称为i次项,ai称为i次项的系数.给出一个一元多项式各项的次数和系数,请按照如下规定的格式要求输出该多项式:1. 多项式中自变量为x,从左到右按照次数递减顺序给出多项式.2. 多项式中只包含系数不为0 的项.3. 如果多项式n 次项系数为正,则多项式开头不出现“+”号,如果多项式n 次项系数为负,则多项式以“-”号开头.4. 对于不是最高次的项,…

比较坑的水题,首项前面的符号,-1,+1,只有数字项的时候要输出0. 感受一下这些数据 160 0 0 0 0 0 0 0 0 -10 0 0 0 0 0 0 0 0 10 0 0 0 0 0 0 0 0 01 0 0 0 0 0 0 0 0 0-1 0 0 0 0 0 0 0 0 0-1 -1 -1 -41 -1 -1 -1 -1 -1 -1-1 5 -2 0 0 0 0 0 0 01 1 1 1 1 1 1 1 1 1-1 -1 -1 -1 -1 -1 -1 -1 -1 -10 0 0 0…

Problem Description We have learned how to obtain the value of a polynomial when we were a middle school student. If f(x) is a polynomial of degree n, we can let.If we have x, we can get f(x) easily. But a computer can not understand the expression l…

题意: INPUT: The input of the first line is an integer T, which is the number of test data (T<120). Then T data follows. For each data, there are 10 integer numbers on one line, which are the coefficients and constant a, b, c, d, e, f, g, h, i, j of th…

Xiangqi Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=4121 Description Xiangqi is one of the most popular two-player board games in China. The game represents a battle between two armies with the goal of captu…

Description SVM(Support Vector Machine)is an important classification tool, which has a wide range of applications in cluster analysis, community division and so on. SVM The kernel functions used in SVM have many forms. Here we only discuss the funct…