PAT1071. Speech Patterns (25)】的更多相关文章

题目要求的Word定义 Here a "word" is defined as a continuous sequence of alphanumerical characters separated by non-alphanumerical characters or the line beginning/end.  所以 can""can""can 中应该是3个单词 #include <iostream> #include &l…
1071. Speech Patterns (25) 时间限制 300 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HOU, Qiming People often have a preference among synonyms of the same word. For example, some may prefer "the police", while others may prefer "the cops&qu…
1071 Speech Patterns (25 分)   People often have a preference among synonyms of the same word. For example, some may prefer "the police", while others may prefer "the cops". Analyzing such patterns can help to narrow down a speaker's id…
People often have a preference among synonyms of the same word. For example, some may prefer "the police", while others may prefer "the cops". Analyzing such patterns can help to narrow down a speaker's identity, which is useful when v…
People often have a preference among synonyms of the same word. For example, some may prefer "the police", while others may prefer "the cops". Analyzing such patterns can help to narrow down a speaker's identity, which is useful when v…
People often have a preference among synonyms of the same word. For example, some may prefer "the police", while others may prefer "the cops". Analyzing such patterns can help to narrow down a speaker's identity, which is useful when v…
简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include<string> #include<iostream> #include<algorithm> using namespace std;…
分割字符串的用法+map映射给出input中出现次数最多的单词,如果次数相同,给出按字典序最小的. 这里我用了自定义分隔符来读取字符串,方法如下: //按照定义的分隔符d来分割字符串,对str进行读取 const char *d = "\n\'\"\? ";//换行,',",?,空格 char *p; p = strtok(str,d); //这样做的主要原因是避免最后输出换行 while(p) { //对p进行处理 p=strtok(NULL,d); //读取下一…
一.技术总结 开始拿到这道题目时,思考的是我该如何区分它们每一个单词,不知道这里还是要学习得知在cctype头文件中有一个函数用于查看是否为0~9.a~z.A~Z,就是isalnum(),又因为题目中要求不区分大小写,有一个函数tolower(),toupper()要学会合理利用. 然后就是使用map技术了,默认初始化为0如果是string,int,可以直接mp[]++; 然后就是键值和值mp->first,mp->second; 二.参考代码 #include<iostream>…
题意: 输入一行字符串,输出出现过次数最多的由字母和数字组成的字符串以及它出现的次数(对大小写不敏感,输出全部输出小写). AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; string word; map<string,int>mp; string s; int main(){ ios::sync_with_stdio(false); cin.t…