题目意思:递增数组,找到目标数的范围,找不到则返回[-1,-1] 思路:折半查找 class Solution { public: vector<int> searchRange(vector<int>& nums, int target) { ,end=nums.size()-; vector<int> ans; while(start<=end){ ; if(nums[temp]>target){ end=temp-; } else if(num…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 34: Search for a Rangehttps://oj.leetcode.com/problems/search-for-a-range/ Given a sorted array of integers, find the starting and ending position of a given target value.Your algorithm's r…

leetcode - 34. Search for a Range - Medium descrition Given an array of integers sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the ta…

原题目:Search for a Range, 现在题目改为: 34. Find First and Last Position of Element in Sorted Array Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity…

Search for a Range Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For ex…

Search for a Range Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For ex…

Search for a Range Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For ex…

题目: Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given [5,…

https://leetcode.com/problems/search-for-a-range/ Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the…

Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given [5, 7,…

Given an array of integers sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For e…

1 题目: Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given […

题目描述: Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example, Given…

Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given [5, 7,…

一天一道LeetCode系列 (一)题目 Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For…

题目链接: https://leetcode.com/problems/search-for-a-range/?tab=Description   Problem: 在已知递减排序的数组中,查找到给定数字的起止下标   采用两遍扫描: 第一遍扫描得到给定数字的起始下标,(从下标i==0开始到nums.lenght-1) 第二遍扫描从第一遍扫描得到的下标开始进行扫描    参考代码: package leetcode_50; /*** * * @author pengfei_zheng * 数组中…

Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example, Given [5, 7,…

1. 原题链接 https://leetcode.com/problems/search-for-a-range/description/ 2. 题目要求 给定一个按升序排列的整型数组nums[ ]和目标值target(int类型),如果数组中存在目标值,返回目标值在数组中的起始位置和结束位置,[start, end].不存在返回 [-1, -1]. 3. 解题思路 思路一:暴力解决,遍历数组进行匹配,时间复杂度O( n ) 4. 代码实现 package com.huiAlex; public…

最近做的题记录下. 258. Add Digits Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. For example: Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it. int addDigi…

LintCode 61. Search for a Range (Medium) LeetCode 34. Search for a Range (Medium) class Solution { private: int findBound(vector<int> &A, int target, bool findLowerBound) { int L = 0, R = A.size() - 1; while (L <= R) { int M = L + (R - L) / 2…

题目:搜索目标范围 难度:Medium 题目内容: Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in th…

Search Insert Position Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples. [1,3,5…

索引:[LeetCode] Leetcode 题解索引 (C++/Java/Python/Sql) Github: https://github.com/illuz/leetcode 035. Search for a Range (Medium) 链接: 题目:https://leetcode.com/problems/search-for-a-range/ 代码(github):https://github.com/illuz/leetcode 题意: 在有序数组中找到一个数的范围.(由于数…

1. Search in Rotated Sorted Array Suppose an array sorted in ascending order is rotated(轮流,循环) at some pivot(枢轴; 中心点) unknown to you beforehand(提前; 事先). (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If foun…

题目意思:在递增数组中找到目标数的位置,如果目标数不在数组中,返回其应该在的位置. 思路:折半查找,和相邻数比较,注意边界 class Solution { public: int searchInsert(vector<int>& nums, int target) { ,end=nums.size()-; ; while(start<=end){ flag=(start+end)/; if(nums[flag]==target)return flag; else if(num…

一次总结两道题,两道题目都比较基础 Description:Write a function to find the longest common prefix string amongst an array of strings. 分析: 这道题目最重要的知道什么叫prefix前缀, 否则一不小心就做成了最长子序列.前缀就是两个序列的前多少位 都要是一样的,不能跳着对齐,这样就比较简单了,也可以求很多个序列的公共前缀. class Solution { public: string longe…

1.问题描述 Given an array of integers sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]…

Search for a RangeGiven a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For exa…

题目: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. 翻译: 给定一组整数,两个数字的返回索引,它们的和会等于一个特定…

61. Search for a Range[medium] Given a sorted array of n integers, find the starting and ending position of a given target value. If the target is not found in the array, return [-1, -1]. Have you met this question in a real interview? Yes Example Gi…