http://poj.org/problem?id=1160 算水过的吧 四重循环没优化 CZ说爆可过 就爆了 dp[i][j] = min(dp[i][j],dp[i-1][g]-s) 第i个点建在第j个村庄上 s 是这个点比上个点少的距离 #include <iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<stdlib.h> #include&…

Description There is a straight highway with villages alongside the highway. The highway is represented as an integer axis, and the position of each village is identified with a single integer coordinate. There are no two villages in the same positio…

这题和"山区建小学"除了输入不同,其他都一样.(解析可见我的上一篇随笔) 但是,这次我对dis[][]加了一个优化,画一下图就可明白. 1 #include<cstdio> 2 #include<cstdlib> 3 #include<cstring> 4 5 const int N=310,M=35; 6 int s[N],f[N][M],dis[N][N]; 7 8 int mmin(int x,int y) {return x<y?x:y…

LightOJ 1033  Generating Palindromes(dp) 题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=87730#problem/A 题目: Description By definition palindrome is a string which is not changed when reversed. "MADAM" is a nice example of palindrome.…

lightOJ 1047   Neighbor House (DP) 题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=87730#problem/C 题目: Description The people of Mohammadpur have decided to paint each of their houses red, green, or blue. They've also decided that no two n…

UVA11125 - Arrange Some Marbles(dp) option=com_onlinejudge&Itemid=8&category=24&page=show_problem&problem=2066" target="_blank" style="">题目链接 题目大意:给你n种不同颜色的弹珠.然后给出每种颜色的弹珠的个数,如今要求你将这些弹珠排序,要求同样颜色的部分最多3个.然后同样颜色的弹珠称…

[POJ 3071] Football(DP) Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 4350   Accepted: 2222 Description Consider a single-elimination football tournament involving 2n teams, denoted 1, 2, -, 2n. In each round of the tournament, all tea…

学习qzz的命名,来写一篇关于动态规划(dp)的入门博客. 动态规划应该算是一个入门oier的坑,动态规划的抽象即神奇之处,让很多萌新 萌比. 写这篇博客的目标,就是想要用一些容易理解的方式,讲解入门动态规划的真正意义. 奶萌兔的温馨提示:建议先理解dfs哦~(本文以一种较为新奇的方式解释DP) 动态规划 那什么是动态规划? 来问问神奇的奶萌兔吧(强行盗梗)! (奶萌兔来给你讲解啦~虽然还在睡觉=w=) 动态规划(英语:Dynamic programming,简称DP)是一种在数学.管理科学.计…

Tour(dp) 给定平面上n(n<=1000)个点的坐标(按照x递增的顺序),各点x坐标不同,且均为正整数.请设计一条路线,从最左边的点出发,走到最右边的点后再返回,要求除了最左点和最右点之外每个点恰好经过一次,且路径总长度最短.两点间的长度为它们的欧几里得距离. 首先转换一下题意,可以看作找到两条不相交(除了起点终点)且总长最短的路径.这种题型有一个套路,就是让两个点再路径上模拟前进.如果用\(d(i, j)\)表示第一个人走到i,第二个人走到j,那么就不能设计出转移方程,因为不能保证两个人…

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