Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

https://leetcode.com/problems/data-stream-as-disjoint-intervals/ Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the da…

问题描述: Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. 解题思路: 这道题是目前最新的题,其实思路很容易找到,难点在于考虑到所有的可能的情形. 首先要确定类必须有一个保存当前结果的集合类List<Interval>,其元素的按Interval的起始值的大小排序,…

Plz take my miserable life T T. 和57 insert interval一样的,只不过insert好多. 可以直接用57的做法一个一个加,然后如果数据大的话,要用tree map,可以迅速找到切入点. Key用的左边界. /** * Definition for an interval. * public class Interval { * int start; * int end; * Interval() { start = 0; end = 0; } * I…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

数据流合并成区间,每次新来一个数,表示成一个区间,然后在已经保存的区间中进行二分查找,最后结果有3种,插入头部,尾部,中间,插入头部,不管插入哪里,都判断一下左边和右边是否能和当前的数字接起来,我这样提交了,发现错了,想到之前考虑要不要判重,我感觉是这个问题,然后就是在二分查找的时候,判断一下左右区间是否包含当前的值,包含就直接返回. /** * Definition for an interval. * struct Interval { * int start; * int end; * I…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 Design a d…

常规方法 超时 class MedianFinder { vector<int> coll; public: MedianFinder(){ } void heapfu(vector<int>& coll,int idx,int max){ int left=2*idx+1,right=2*idx+2; int largest=idx; if(left<max&&coll[left]>coll[idx]) largest=left; if(rig…

题目如下:(https://leetcode.com/problems/find-median-from-data-stream/) Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] …

Find Median from Data Stream Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is…

Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 Design a d…

题目: Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 Design…

https://leetcode.com/problems/find-median-from-data-stream/ Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the m…

LintCode 81. Data Stream Median (Hard) 思路: 用一个大根堆保存较小的一半数, 一个小根堆保存较大的一半数. 每次根据num和两个堆顶的数据决定往哪个堆里面放. 放完后进行平衡确保两个堆的size差不超过1. 利用两个堆的size和堆顶值计算median. 大根堆可以表示为priority_queue<int, vector<int>, less<int>>, 其实priority_queue<int>默认就是大根堆.…

Question Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 D…

Data Stream Median Numbers keep coming, return the median of numbers at every time a new number added. Have you met this question in a real interview? Example For numbers coming list: [1, 2, 3, 4, 5], return [1, 1, 2, 2, 3]. For numbers coming list:…

git clone时出现 error:inflate:data stream error(incorrect data check) fatal:serrious inflate inconsistency fatal:index-pack failed 经了解,此问题是遗留问题,之前是因为公司对gitlab服务器进行数据迁移而引起这种git clone失败的原因,现象非常奇怪,大部分project是可以clone的,小部分不行,有一些人clone没问题的,有些人就是不行,我被这个问题困扰了好久…

Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. For example, [2,3,4], the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 Design a…

295. Find Median from Data Stream&数据流中的中位数 295. Find Median from Data Stream https://leetcode.com/problems/find-median-from-data-stream/discuss/74062/Short-simple-JavaC%2B%2BPython-O(log-n)-%2B-O(1) 题目 Median is the middle value in an ordered integer…

中位数是有序列表中间的数.如果列表长度是偶数,中位数则是中间两个数的平均值. 例如, [2,3,4] 的中位数是 3 [2,3] 的中位数是 (2 + 3) / 2 = 2.5 设计一个支持以下两种操作的数据结构: void addNum(int num) - 从数据流中添加一个整数到数据结构中. double findMedian() - 返回目前所有元素的中位数. 示例: addNum(1) addNum(2) findMedian() -> 1.5 addNum(3) findMedian…

Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. For example, [2,3,4], the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 Design a…

注意multiset的一个bug: multiset带一个参数的erase函数原型有两种.一是传递一个元素值,如上面例子代码中,这时候删除的是集合中所有值等于输入值的元素,并且返回删除的元素个数:另外一种是传递一个指向某个元素的iterator,这时候删除的就是这个对应的元素,无返回值. https://www.cnblogs.com/lakeone/p/5600494.html 删除的时候一定不能删除指针,只能删除迭代器 leetcode那个题就是在这个地方出错的: Input: [3,2,3…

Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 Design a d…

Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4] , the median is 3 [2,3], the median is (2 + 3) / 2 = 2.5 Design a d…